:53 PM
Subject: RE: JSP pages giving out source code
Apache doesn't understand that *.jsp requests need to be sent to Tomcat.
You need a connector (WARP, JK, or JK2), and if you already have one, it's
misconfigured.
John
-Original Message-
From: Uma Maheswar [mailto:[EMAIL
Hello,
Some of the links in my website to .jsp pages are giving out the source code
and some or not. What is the reason?
e.g http://www.javagalaxy.com/sss.jsp gives out source code (not true
link)
where as http://www.javagalaxy.com:8080/ss/s.jsp will work.
How to correct this? Any
Hello,
I cannot view the Tomcat Console. I am using Tomcat 4.0 on Win XP. Also, I
cannot start the Tomcat from
Start - Programmes - Apache Tomcat. I need to go to the Control Panel -
Admin Tools - Services and then start the Tomcat over there.
Can any one tell me what is wrong? I am also using
or deinstall the service
from the command line.
Andreas
On 5 Oct 2002 at 7:54, Uma Maheswar wrote:
Hello,
I cannot view the Tomcat Console. I am using Tomcat 4.0 on Win XP. Also,
I
cannot start the Tomcat from
Start - Programmes - Apache Tomcat. I need to go to the Control Panel -
Admin
Hi Reynir,
I do not have any error message. If I need to start the Tomcat in my PC
running on Win XP, I need to go to Start - Control Panel - Admin Tools -
Services and then start the Tomcat. There is no other option for me than
this.
Now the Tomcat gets started if I do so. But I wanted to view
Hi Reynir,
I tried it, I got this messages
C:\PROGRA~1\Apache Tomcat 4.0\bincatalina run
Using CATALINA_BASE: ..
Using CATALINA_HOME: ..
Using CLASSPATH: ..\bin\bootstrap.jar;c:/j2sdk1.4.0/bin;\lib\tools.jar
Using JAVA_HOME: c:/j2sdk1.4.0/bin;
The system cannot find the path specified.
Reynir,
I tried this and it gave me some error messages. Can you suggest me now?
Uma
C:\PROGRA~1\Apache Tomcat 4.0\bincatalina run
Using CATALINA_BASE: ..
Using CATALINA_HOME: ..
Using CLASSPATH: ..\bin\bootstrap.jar;c:/j2sdk1.4.0/bin;\lib\tools.jar
Using JAVA_HOME: c:/j2sdk1.4.0/bin;
Reynir,
I never changed the server.xml file. I dont know that stuff. Can you tell me
how to change WARP?
Thanks
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Can any one tell me about WARP? Please help me. My problem is listed below.
Thanks
Uma
C:\PROGRA~1\Apache Tomcat 4.0\bincatalina run
Using CATALINA_BASE: ..
Using CATALINA_HOME: ..
Using CLASSPATH:
..\bin\bootstrap.jar;c:/j2sdk1.4.0/bin;\lib\tools.jar
Using JAVA_HOME:
Hi,
Its already same in the server.xml file. I am attaching the file for your
review. Please check it
Uma
!-- Example Server Configuration File --
!-- Note that component elements are nested corresponding to their
parent-child relationships with each other --
!-- A Server is a singleton
George,
Then which server.xml file is this taking? I got this file from
tomcat/conf/server.xml. Please advice.
Uma
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Hello,
I cannot view the Tomcat Console. I am using Tomcat 4.0 on Win XP. Also, I
cannot start the Tomcat from
Start - Programmes - Apache Tomcat. I need to go to the Control Panel -
Admin Tools - Services and then start the Tomcat over there.
Can any one tell me what is wrong? I am also using
Hi,
I need help writing a bean inside my JSP programme. I am also attaching my JSP
programme, please check it and do the need ful changes.
% page
import=java.sql.*,java.io.*,javax.servlet.*,javax.servlet.http.*,java.util.* %
html
%!
String
HI,
I need help from any of you. I need a programme to upload an image to the database
while submitting a form. If any one is having the source code pls help me.
Regards
Uma
-
From: Uma Maheswar [EMAIL PROTECTED]
To: Tomcat Users List [EMAIL PROTECTED]
Sent: Monday, March 04, 2002 10:49 AM
Subject: Pls Help!! Uploading an image
HI,
I need help from any of you. I need a programme to
upload an image to the
database while submitting a form. If any one is having
/struts
It has an easy way to get multipart content from a form, including an easy
example, but there is a learning curve to setting up struts itself.
The code is not going to just appear before your eyes unfortunately :)
- Brett
-Original Message-
From: Uma Maheswar [mailto:[EMAIL
Hi,
I wanted to write a java bean inside my JSP programme. My requirement is like this
%
Connection con = (.);
statement = con.createStatement();
request.getParameter(name);
request.getParameter(phone);
rs = st.executeQuery(select * from uma where name=+name);
if(rs.next())
{
Hi,
I have a doubt, I have a form that has name and his phone number, both the fields are
optional. I declared name as VARCHAR and number as INTEGER in my SQL database. When
the user leaves the fild empty, I get an error with the number field as
NumberFormatException.
So , What I need to do
Hi,
There is a ready made programme out there in www.globalleafs.com . You can
download it from our site.
Uma
- Original Message -
From: Simon [EMAIL PROTECTED]
To: Tomcat Users List [EMAIL PROTECTED]
Sent: Friday, February 22, 2002 4:01 AM
Subject: Java servlet and mailing
Dear,
Hi,
Please help me with this. Please see the code below. It doesn't work, if I give the
correct id and password.But it works if I say (!rs.next()). The same type of programme
worked for me in case of other tables. Could any one pls help me solve this problem.
String id =
Hi friends,
I am doing a project now. I am trying to register a user into the database using
Signup.java (Servlet). I did the code and it worked fine till some days but giving me
problems now. It says that any user who wants to signup is already present in the
database. I am attaching my java
Nachricht-
Von: Uma Maheswar [mailto:[EMAIL PROTECTED]]
Gesendet: Dienstag, 19. Februar 2002 15:36
An: Tomcat Users List
Betreff: Signup servlet
snip/
the database. I am attaching my java file here. Please check
snip/
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Hi,
There is no error in this. The servlet is working fine, but the query is
giving me problem. When the user in the database is not present also, it
says that the user is present in the database. Please check this.
Uma
- Original Message -
From: Vercesi Paolo [EMAIL PROTECTED]
To:
Hi friends,
I am doing a project now. I am trying to register a
user into the database using Signup.java (Servlet). I did the code and it worked
fine till some days but giving me problems now. It says that any user who wants
to signup is already present in the database. I am attaching my
Hi,
I wanted to know if there is any possiblility of getting all the values from a
Database in a single command.
Example:
I am using it in this way in a browser select * from and here is a drop down box
which contains table names as register,pc,signup . I select the table I need from
the
Hi,
Thanks for your replies. I tested both of your methods and mine too. But in
all the cases I found the date to be inserted Random as 1899 or 1905 or
so on.
cal = Calendar.getInstance();
cal.set(year,month,date);
sqlDate = new java.sql.Date(cal.getTime().getTime());
or
totdate =
Hi,
I have a web site www.globalleafs.com . I have downlaoded Tomcat4.0 . I have hosted my
site with Indiaaccess,India. They are using Apache Tomcat 4.0. I wanted to configure
my tomcat in such a way that, I can see the System.out.println statements? i.e to
see the console of Apache Tomcat 4.0
Hi,
I am using Apache Tomcat4.0. I am doing a project in Servlets. I do not get my files
working on IE with this kind of URL
http://globalleafs.com:8080/globalleafs/servlet/TestServlet
But the same URL works fine in Netscape. What could be the problem?
Uma
.what version of
IE
you are using?
Ahmed
- Original Message -
From: Uma Maheswar [EMAIL PROTECTED]
To: Tomcat Users List [EMAIL PROTECTED]
Sent: Thursday, February 07, 2002 8:17 PM
Subject: Problem with IE
Hi,
I am using Apache Tomcat4.0. I am doing a project in Servlets. I do
Hi Brian,
It is a sample one that I gave you, It is working for me too. Please try
this
http://www.globalleafs.com/Login.html
User ID: kiran
Password: kiran
and then when you try clicking on any URL, you get HTTP 404 File not found.
But the same works fine in Netscape. Please check it.
Uma
Hi,
I am using JavaWebServer2.0(Trial Version) in WinXP. I have downloaded Tomcat (.exe)
file. when I try to install it , it says JDK is not found. I have JDK installed with
Visual Cafe in my PC. What should I do now?
Help me.
Uma
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