Hi All, Could you please help me to fix the below issue using spark 2.4 , scala 2.12
How do we extract's the multiple values in the given file name pattern using spark/scala regular expression.please give me some idea on the below approach. object Driver { private val filePattern = xyzabc_source2target_adver_1stvalue_([a-zA-Z0-9]+)_2ndvalue_([a-zA-Z0-9]+)_3rdvalue_([a-zA-Z0-9]+)_4thvalue_ ([a-zA-Z0-9]+)_5thvalue_([a-zA-Z0-9]+)_6thvalue_([a-zA-Z0-9]+)_7thvalue_([a-zA-Z0-9]+)".r How to get all 7 values like "([a-zA-Z0-9]+)" from above regular expression pattern using spark scala and assigned it to the below processing method , i.e. case class schema fields def processing(x:Dataset[someData]){ x.map{ e => caseClassSchema( Field1 = 1stvalue Field2 = 2ndvalue Field3 = 3rdvalue Field4 = 4thvalue Field5 = 5thvalue Field6 = 6thvalue Field7 = 7thvalue ) } } Thanks Anbu -- Sent from: http://apache-spark-user-list.1001560.n3.nabble.com/ --------------------------------------------------------------------- To unsubscribe e-mail: user-unsubscr...@spark.apache.org