Re: [jxpath] How to add an entry to a list?

[Bruno P. Kinoshita]

>Ok.  Does it seem like mitigating this might be a reasonable enhancement for 
>JXPath?  I don't know yet how it would work, but I see it as a flag that when 
>on, would simply deal with this by extending the list automatically.

I am not sure. You can file an issue for that if you'd like. From what I 
understood reading some parts of the code (e.g. ValueUtils#setValue) this is by 
design. You are using a List, so that worked in your case. But should you had 
another collection, I believe you would get a UnsupportedOperationException.


There may be other approaches to solving this issue that I am not aware of. But 
in case you build a good argument in your issue in JIRA, it may be implemented 
in jxpath.

Cheers
Bruno


From: "KARR, DAVID" 
To: Commons Users List ; Bruno P. Kinoshita 
 
Sent: Friday, 16 June 2017 3:37 AM
Subject: RE: [jxpath] How to add an entry to a list?



> -Original Message-
> From: Bruno P. Kinoshita [mailto:brunodepau...@yahoo.com.br.INVALID]
> Sent: Thursday, June 15, 2017 2:51 AM
> To: Commons Users List 
> Subject: Re: [jxpath] How to add an entry to a list?
> 
> Thanks for the link David. Posted a complete reply there, but here's the
> TL;DR.
> 
> The only way I found of doing that, was by pre-populating your list with
> an empty element. That way, /numbers[1] calls List#set(0, "123") with no
> exceptions.

Ok.  Does it seem like mitigating this might be a reasonable enhancement for 
JXPath?  I don't know yet how it would work, but I see it as a flag that when 
on, would simply deal with this by extending the list automatically.

> 
> From: "KARR, DAVID" 
> To: Commons Users List ; Bruno P. Kinoshita
> 
> Sent: Thursday, 15 June 2017 3:13 AM
> Subject: RE: [jxpath] How to add an entry to a list?
> 
> 
> 
> > -Original Message-
> > From: Bruno P. Kinoshita [mailto:brunodepau...@yahoo.com.br.INVALID]
> > Sent: Wednesday, June 14, 2017 3:18 AM
> > To: Commons Users List 
> > Subject: Re: [jxpath] How to add an entry to a list?
> >
> > Hi David,
> >
> > Do you have some code you could share? Maybe looking at your code
> others
> > (I would try as well, but can't promise will know how to help) might
> be
> > able to help.
> 
> Thanks for replying.  I posted more detailed code samples on SO:
> https://urldefense.proofpoint.com/v2/url?u=https-
> 3A__stackoverflow.com_questions_44530112_how-2Dto-2Dget-2Djxpath-2Dto-
> 2Dcleanly-2Dset-2Dlist-2Dcollection-2Dentries=DwIFaQ=LFYZ-
> o9_HUMeMTSQicvjIg=OsTemSXEn-xy2uk0vYF_EA=nfT2LEhdW7RV4azBV5z7cO-
> vMKzYetKiHBtDCkt0CoI=AXR_qT2s9pltw3Q7IPZwifyv91V3YxSISo5Jt_B3KE4=  .
> 
> > 
> > From: "KARR, DAVID" 
> > To: Commons Users List 
> > Sent: Wednesday, 14 June 2017 6:11 AM
> > Subject: [jxpath] How to add an entry to a list?
> >
> >
> >
> > If a property in a bean I'm trying to manipulate with jxpath is a
> List,
> > how do I set a value in an entry of that list?
> >
> >
> > I read the info at "Modifying Object Graphs", but it's still not clear
> > from this how I would do this.
> >
> >
> > I've figured out how to get the list created, either with an explicit
> > "setValue()", or with a "createPathAndSetValue()" along with a factory
> > and createObject() method set to look for that property, but if I try
> to
> > set a value into the list, it fails apparently because the list is
> still
> > zero size.
> >
> >
> > The only way I can hack this to work is to initialize the list
> property
> > to an ArrayList with the required number of dummy elements already
> added
> > to it, so the subscript reference works.
> >
> >
> > I'm using JXPath so that I can write tests with a little less
> > boilerplate and focus on pure business logic.  Ideally, I'd like
> JXPath
> > (or perhaps a factory) to do the "obvious stuff".
> >
> >
> >
> > -
> >
> > To unsubscribe, e-mail: user-unsubscr...@commons.apache.org
> >
> > For additional commands, e-mail: user-h...@commons.apache.org
> 
> >
> > -
> > To unsubscribe, e-mail: user-unsubscr...@commons.apache.org
> > For additional commands, e-mail: user-h...@commons.apache.org
> 
> Т�ХF
> �V�7V'67&��R���âW6W"�V�7V'67&��2�6�R��Фf�"FF�F6G2�R��
> �âW6W"ֆV�6�2�6�R��Р

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RE: [jxpath] How to add an entry to a list?

[KARR, DAVID]

> -Original Message-
> From: Bruno P. Kinoshita [mailto:brunodepau...@yahoo.com.br.INVALID]
> Sent: Thursday, June 15, 2017 2:51 AM
> To: Commons Users List 
> Subject: Re: [jxpath] How to add an entry to a list?
> 
> Thanks for the link David. Posted a complete reply there, but here's the
> TL;DR.
> 
> The only way I found of doing that, was by pre-populating your list with
> an empty element. That way, /numbers[1] calls List#set(0, "123") with no
> exceptions.

Ok.  Does it seem like mitigating this might be a reasonable enhancement for 
JXPath?  I don't know yet how it would work, but I see it as a flag that when 
on, would simply deal with this by extending the list automatically.

> 
> From: "KARR, DAVID" 
> To: Commons Users List ; Bruno P. Kinoshita
> 
> Sent: Thursday, 15 June 2017 3:13 AM
> Subject: RE: [jxpath] How to add an entry to a list?
> 
> 
> 
> > -Original Message-
> > From: Bruno P. Kinoshita [mailto:brunodepau...@yahoo.com.br.INVALID]
> > Sent: Wednesday, June 14, 2017 3:18 AM
> > To: Commons Users List 
> > Subject: Re: [jxpath] How to add an entry to a list?
> >
> > Hi David,
> >
> > Do you have some code you could share? Maybe looking at your code
> others
> > (I would try as well, but can't promise will know how to help) might
> be
> > able to help.
> 
> Thanks for replying.  I posted more detailed code samples on SO:
> https://urldefense.proofpoint.com/v2/url?u=https-
> 3A__stackoverflow.com_questions_44530112_how-2Dto-2Dget-2Djxpath-2Dto-
> 2Dcleanly-2Dset-2Dlist-2Dcollection-2Dentries=DwIFaQ=LFYZ-
> o9_HUMeMTSQicvjIg=OsTemSXEn-xy2uk0vYF_EA=nfT2LEhdW7RV4azBV5z7cO-
> vMKzYetKiHBtDCkt0CoI=AXR_qT2s9pltw3Q7IPZwifyv91V3YxSISo5Jt_B3KE4=  .
> 
> > 
> > From: "KARR, DAVID" 
> > To: Commons Users List 
> > Sent: Wednesday, 14 June 2017 6:11 AM
> > Subject: [jxpath] How to add an entry to a list?
> >
> >
> >
> > If a property in a bean I'm trying to manipulate with jxpath is a
> List,
> > how do I set a value in an entry of that list?
> >
> >
> > I read the info at "Modifying Object Graphs", but it's still not clear
> > from this how I would do this.
> >
> >
> > I've figured out how to get the list created, either with an explicit
> > "setValue()", or with a "createPathAndSetValue()" along with a factory
> > and createObject() method set to look for that property, but if I try
> to
> > set a value into the list, it fails apparently because the list is
> still
> > zero size.
> >
> >
> > The only way I can hack this to work is to initialize the list
> property
> > to an ArrayList with the required number of dummy elements already
> added
> > to it, so the subscript reference works.
> >
> >
> > I'm using JXPath so that I can write tests with a little less
> > boilerplate and focus on pure business logic.  Ideally, I'd like
> JXPath
> > (or perhaps a factory) to do the "obvious stuff".
> >
> >
> >
> > -
> >
> > To unsubscribe, e-mail: user-unsubscr...@commons.apache.org
> >
> > For additional commands, e-mail: user-h...@commons.apache.org
> 
> >
> > -
> > To unsubscribe, e-mail: user-unsubscr...@commons.apache.org
> > For additional commands, e-mail: user-h...@commons.apache.org
> 
> Т�ХF
> �V�7V'67&��R���âW6W"�V�7V'67&��2�6�R��Фf�"FF�F6G2�R��
> �âW6W"ֆV�6�2�6�R��Р
> 
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> To unsubscribe, e-mail: user-unsubscr...@commons.apache.org
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Re: [jxpath] How to add an entry to a list?

[Bruno P. Kinoshita]

Thanks for the link David. Posted a complete reply there, but here's the TL;DR.

The only way I found of doing that, was by pre-populating your list with an 
empty element. That way, /numbers[1] calls List#set(0, "123") with no 
exceptions.

Hope that helps
Bruno




From: "KARR, DAVID" 
To: Commons Users List ; Bruno P. Kinoshita 
 
Sent: Thursday, 15 June 2017 3:13 AM
Subject: RE: [jxpath] How to add an entry to a list?



> -Original Message-
> From: Bruno P. Kinoshita [mailto:brunodepau...@yahoo.com.br.INVALID]
> Sent: Wednesday, June 14, 2017 3:18 AM
> To: Commons Users List 
> Subject: Re: [jxpath] How to add an entry to a list?
> 
> Hi David,
> 
> Do you have some code you could share? Maybe looking at your code others
> (I would try as well, but can't promise will know how to help) might be
> able to help.

Thanks for replying.  I posted more detailed code samples on SO: 
https://stackoverflow.com/questions/44530112/how-to-get-jxpath-to-cleanly-set-list-collection-entries
 .

> 
> From: "KARR, DAVID" 
> To: Commons Users List 
> Sent: Wednesday, 14 June 2017 6:11 AM
> Subject: [jxpath] How to add an entry to a list?
> 
> 
> 
> If a property in a bean I'm trying to manipulate with jxpath is a List,
> how do I set a value in an entry of that list?
> 
> 
> I read the info at "Modifying Object Graphs", but it's still not clear
> from this how I would do this.
> 
> 
> I've figured out how to get the list created, either with an explicit
> "setValue()", or with a "createPathAndSetValue()" along with a factory
> and createObject() method set to look for that property, but if I try to
> set a value into the list, it fails apparently because the list is still
> zero size.
> 
> 
> The only way I can hack this to work is to initialize the list property
> to an ArrayList with the required number of dummy elements already added
> to it, so the subscript reference works.
> 
> 
> I'm using JXPath so that I can write tests with a little less
> boilerplate and focus on pure business logic.  Ideally, I'd like JXPath
> (or perhaps a factory) to do the "obvious stuff".
> 
> 
> 
> -
> 
> To unsubscribe, e-mail: user-unsubscr...@commons.apache.org
> 
> For additional commands, e-mail: user-h...@commons.apache.org

> 
> -
> To unsubscribe, e-mail: user-unsubscr...@commons.apache.org
> For additional commands, e-mail: user-h...@commons.apache.org

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Re: [jxpath] How to add an entry to a list?

[Bruno P. Kinoshita]

Hi David,

Do you have some code you could share? Maybe looking at your code others (I 
would try as well, but can't promise will know how to help) might be able to 
help.

Cheers
Bruno



From: "KARR, DAVID" 
To: Commons Users List  
Sent: Wednesday, 14 June 2017 6:11 AM
Subject: [jxpath] How to add an entry to a list?



If a property in a bean I'm trying to manipulate with jxpath is a List, how do 
I set a value in an entry of that list?


I read the info at "Modifying Object Graphs", but it's still not clear from 
this how I would do this.


I've figured out how to get the list created, either with an explicit 
"setValue()", or with a "createPathAndSetValue()" along with a factory and 
createObject() method set to look for that property, but if I try to set a 
value into the list, it fails apparently because the list is still zero size.


The only way I can hack this to work is to initialize the list property to an 
ArrayList with the required number of dummy elements already added to it, so 
the subscript reference works.


I'm using JXPath so that I can write tests with a little less boilerplate and 
focus on pure business logic.  Ideally, I'd like JXPath (or perhaps a factory) 
to do the "obvious stuff".



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