Blaze sez:
That being said, I do believe Rossi might have messed with the fuel or the
extraction of the fuel in some way to mis direct, so if you want to
re-write your analysis to hold for that, I'd be cool with it.
I just won't accept that the scientists purposely lied.
So, how much money
What you say, Dave, is entirely true and always pragmatically wrong. Most
DAQ systems do not sample simultaneously and have an input capacitance that
provides averaging. Thus, you will always be reading average current
between samples and average voltage. Computing power from average current
If the internal current control feedback mechanism is slow to act, then the
output current might indeed change significantly. I have never put a constant
current supply under careful supervision before but assumed that the guys
designing them would go to lengths to ensure that they in fact
Dear Friends,
I have just published.
http://egooutpeters.blogspot.ro/2014/10/about-new-negative-information-and.html
you will see that my Open Letter had limited success but I created a new
inspiring metaphor of LENR that will have success commensurate with the OL.
But it is real, you will
I have no first hand knowledge one way or the other [this was not my
assertion]. I believe Dr. McKubre to be an outstanding researcher and have
no reason to believe this escaped his attention. Even if it did, it would
only be a minor error and does not alter conclusions.
It will make a
The information that I have received, which might not be totally accurate, is
that most of the testing is done in constant current mode operation. The
supply current would be monitored and then plenty of negative feedback would
come into play to ensure that the current remains fixed. This
2014-10-24 23:14 GMT+02:00 Jed Rothwell jedrothw...@gmail.com:
McKubre never reported a 3% gain. Even with his calorimeter that would be
in the margin of error at the bottom of the scale, although he can detect
the difference between, say, 40% and 43%. As I recall, McKubre reported
gains
The note from Kur is seriously in error. Dr. McKubre was entirely correct in
his assumptions about the constant current operation of his cells. As he
explained, the AC noise voltage variations average out over the long term and
do not contribute to the net input power calculations and hence
Nobody really knows how the E-Cat radiates energy. Ni/H is completely
undefined technology. No assumptions should be made about LENR. The IR
camera calibration is an excellent opportunity to made bad assumptions
about the calibration of these sensors. This is the main reason why I
believe that an
Axil Axil janap...@gmail.com wrote:
Nobody really knows how the E-Cat radiates energy.
It radiates heat energy according to the Stefan-Boltzmann law, like any
other object. The source of the heat is irrelevant. All hot objects radiate
heat the same way, and they all turn the same incandescent
I hate to say this, but what you say is absolutely wrong. You could only
do as you describe if the voltage being averaged is the RMS voltage. You
cannot take the average voltage and multiply it by the average current to
get average power. For example, suppose that the voltage was
On 10/27/2014 03:08 PM, Jed Rothwell wrote:
All hot objects radiate heat the same way, and they all turn the same
incandescent color at a given temperature.
Everything I read tells me this is modified by a materials 'emissivity'
factor.
The amount of thermal energy an object will radiate is
I believe that the E-Cat is completely enclosed in a high temperature boson
condensate. How that condensate might radiate energy is UNKNOWN. This
condensate could be releasing energy at a single IR frequency like a
laser might. The test team should have run a spectrum analysis on this
reactor's
H Veeder hveeder...@gmail.com wrote:
​Unless heat is absorbed during charging and is released during discharge
a calorimeter can't tell you if an endothermic reaction occurred.
The heat being absorbed is the definition of an endothermic reaction.
That's exactly what it is. Even if the energy
From: Jed Rothwell jedrothw...@gmail.com
Sent: Monday, October 27, 2014 12:08:08 PM
Axil Axil janap...@gmail.com wrote:
Nobody really knows how the E-Cat radiates energy.
It radiates heat energy according to the Stefan-Boltzmann law, like any other
object. The source of the heat is
Jed--
Your understanding of black body radiation is different from mine relative to
its equilibrium temperature.
Note that I have suggested that my understanding of temperature and radiation
emitted by a black body depend upon an equilibrium condition. The substance
with the light emission
My analysis of IR calorimetry and Black Body radiation is here :
http://lenr.qumbu.com/blackbody_141027A.php
I was persuaded by McKubre and Docherty not to downgrade my results to failed
experiment.
I've also updated my banding paper :
This is not my understanding. Most wattmeters that are implemented as you
describe require the wattmeter to be the entire target load. Otherwise,
there is no error-proof way to know how much power is dissipated in the
wattmeter in relation to that which is dissipated in the device.
Typical
Bob Higgins rj.bob.higg...@gmail.com wrote:
This is not my understanding. Most wattmeters that are implemented as you
describe require the wattmeter to be the entire target load. Otherwise,
there is no error-proof way to know how much power is dissipated in the
wattmeter in relation to that
In thermal wattmeter, the series wire that is heated measures the current
squared, not power. This is useful for measurement of the power to the
load only if the load is resistive and the resistance does not vary because
the power is I^2R. You could measure the voltage squared with a similar
If you stabilize the current at I0 I think that the question of average is
solved.
you have
U(t)=U0+R(t)I0
P(t)=U(t)I0
what is proposed here is that R(t) is hugely unpredictable and changing
quickly.
in fact if you measure U(t) average over the time period, you have simply
the power injected.
Bob Higgins rj.bob.higg...@gmail.com wrote:
. . . So to use such [thermal watt-] meters, you have to presume that you
have no phase shift between the voltage and current (a point of residual
equivocation and error). To insure this is a correct presumption, you need
an oscilloscope to check.
In reply to Jones Beene's message of Sun, 26 Oct 2014 09:05:35 -0700:
Hi,
[snip]
5) The second iteration of the Blue Box for China will contain about
100+ low temp E-Cat sub-units, each with average COP of about 2, but staged
in such a way that the net COP is infinite (which is simple to do,
What a bunch of horse manure. Your enfeebled building is built from
scat. And if God had intended real thinkers to ski, he'd have made
bullshit white.
On 10/26/14, Robert Ellefson vortex-h...@e2ke.com wrote:
Occam's Razor is a tool used by enfeebled minds to construct paper houses
out of
Bob, I take that as a challenge. I am not offended my friend, but find this a
great opportunity to prove what I am saying is correct. I predict that you
will agree with me once you have an opportunity to dig deeper into the subject.
It is not clear to me what you are showing in your
Consider that if you actually have a COP of 2 under a set of conditions, then
changing those conditions should allow for an increase in the COP. Better
insulation for the escape heat flow paths will cause an increase in the core
temperature. If the generated power increases with core
We cannot even assume that it follows the laws of physics?
***A law is just a mathematically rigorous observation. It is not a
dictate from nature. LENR is a field of study precisely because the
laws of physics are being broken. It's as if you took some bricks
and dropped them from the leaning
What is new in LENR is how high power magnetic force interacts with the
vacuum, nuclear matter, and associated orbital electrons.
On Mon, Oct 27, 2014 at 9:35 PM, Kevin O'Malley kevmol...@gmail.com wrote:
We cannot even assume that it follows the laws of physics?
***A law is just a
Well Dave, you have made a good and convincing argument. My hat is off to
you and I need to eat it with a big public helping of crow.
It seems like if we go back to basics, the average power is integral((I
dot V)dt)/integral(dt). If I is a constant, then you can pull I outside
the integral and
On Mon, Oct 27, 2014 at 2:29 PM, Jed Rothwell jedrothw...@gmail.com wrote:
No matter how intense and short the burst of energy is, as long as the
calorimeter walls prevent it from escaping, and it produces enough joules
of heat to be detected, it will be detected.
This is a great advantage of
On Mon, Oct 27, 2014 at 4:53 PM, David Roberson dlrober...@aol.com wrote:
Since we are assuming a symmetrical AC waveform, this is a pretty good
example of that with numerous harmonics that also get into the act.
Is this a safe assumption?
Eric
Thanks Bob for taking the time to follow my discussion. If we are lucky others
will help to inform the skeptics that Dr. McKubre is doing his experimentation
in a manner that we can agree is appropriate.
Don't beat yourself up too badly since I have a hunch that very few others
would have
I suppose I should have stated that in a more appropriate manner. What I was
attempting to get across was that the waveforms must not contain a DC
component. Any DC portion would behave exactly as Dr. McKubre explained and
appear as a valid input signal which remains after averaging and is
On Mon, Oct 27, 2014 at 10:10 PM, David Roberson dlrober...@aol.com wrote:
Let me know if you are still confused since it is important that we set the
records straight and dispose of skeptical ideas.
Unfortunately I don't know enough about electronics yet to have an opinion
on Michael
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