Re: [Vo]:Rossi: fat-cat architecure

2011-10-12 Thread Alan J Fletcher
At 01:19 PM 10/11/2011, Alan J Fletcher wrote: I got confirmation from an observer that Lewan's photo and Rossi's description accurately describe the inside. http://www.nyteknik.se/incoming/article3284879.ece/BINARY/original/DSC_0089_600.jpg The 20x20x4 wafer is mounted at the center of the

[Vo]:Rossi: fat-cat architecure

2011-10-11 Thread Alan J Fletcher
Andrea Rossi October 11th, 2011 at 12:41 PM Dear Gunnar Lindberg: All the box containing the reactor is filled with water. The reactor wafer is cm 20 x 20 x 4 (external dimensions), and to it are welded all the steel wings necessary to exchange all the heat produced inside the reactor. When

Re: [Vo]:Rossi: fat-cat architecure

2011-10-11 Thread Jed Rothwell
Rossi said: The volume free for the water is about 30 liters, so that to fill up it are necessary about 2 hours ( the pump of the primary circuit pumps about 15 liters per hour) . . . This is confusing yet strangely helpful. Didn't he say there are four cells in each reactor box? There are 4

Re: [Vo]:Rossi: fat-cat architecure

2011-10-11 Thread Alan J Fletcher
At 01:50 PM 10/11/2011, Jed Rothwell wrote: Anyway, there are multiple cells and only one cell was in use during this test. I assume each of the 4 cells has its own reservoir, so 30 L / 4 = 7.4 L. That's not my interpretation. The fat-cat is a big tub of overall volume 110 litres. The wafer

Re: [Vo]:Rossi: fat-cat architecure

2011-10-11 Thread Robert Leguillon
In the September report, they drain the water in the E-Cat through the fill port, and 22,400 grams are expelled. This seems to be at or near overflowing, based on the collected water; Also, the E-Cat weighed about a kg more than it started at (this is presumably water retained below the level

Re: [Vo]:Rossi: fat-cat architecure

2011-10-11 Thread Horace Heffner
On Oct 11, 2011, at 2:44 PM, Alan J Fletcher wrote: At 01:50 PM 10/11/2011, Jed Rothwell wrote: Anyway, there are multiple cells and only one cell was in use during this test. I assume each of the 4 cells has its own reservoir, so 30 L / 4 = 7.4 L. That's not my interpretation. The