Peter da Silva wrote:
> I am pretty sure that the code is not legal C

Indeed; C99 and C11 say in 6.3.2.2:
| The (nonexistent) value of a void expression (an expression that has
| type void) shall not be used in any way [...]
and in 6.8.6.4:
| A return statement with an expression shall not appear in a function
| whose return type is void.

(And it has already been fixed two hours ago.)


Regards,
Clemens
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