I am using sqlite3 version 2.8.17 on an Arm Debian Linux system.

I created a test table using these commands from Linux:

"
cat 01_create_tables.sql
CREATE TABLE PV_INTERVALDATA (
   timestamp DATE,
   T_ambient      REAL    NOT NULL,
   T_trunk1       REAL    NOT NULL,
   T_trunk4       REAL    NOT NULL
);

sqlite < 01_create_tables.sql pvintervaldata.sqlite
"

I then went to insert a row into the new database with this C code:

"
#include <stdio.h>
#include <sqlite3.h>

static int callback(void *NotUsed, int argc, char **argv, char **azColName){
  int i;
  for(i=0; i<argc; i++){
    printf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
  }
  printf("\n");
  return 0;
}

int main(int argc, char **argv){
  sqlite3 *db;
  char *zErrMsg = 0;
  int rc;

  rc = sqlite3_open("pvintervaldata.sqlite", &db);
  if( rc ){
    fprintf(stderr, "Can't open database: %s\n", sqlite3_errmsg(db));
    sqlite3_close(db);
    return(1);
  }
  rc = sqlite3_exec(db, "insert into PV_INTERVALDATA
values(datetime('now','localtime'), 24.5, 20, 21);", callback, 0, &zErrMsg);
  if( rc!=SQLITE_OK ){
    fprintf(stderr, "SQL error: %s\n", zErrMsg);
    sqlite3_free(zErrMsg);
  }
  sqlite3_close(db);
  return 0;
}
"

On running the C program I get this error however:

"
SQL error: file is encrypted or is not a database
"

What is going wrong?
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