Alberto Ganesh Barbati wrote:
Hi Everybody,
this might be obvious but I couldn't find an authoritative answer on
stackless.com nor in the archive of this mailing list. The question is
simple: under which license is Stackless distributed? In both the source
distribution and by typing license() all I get is the Python license
from the PSF. Does that apply to all Stackless modifications to Python
also? In case it does apply, is the PSF notice of copyright: "Copyright
(c) 2001, 2002, 2003, 2004, 2005, 2006, 2007, 2008 Python Software
Foundation; All Rights Reserved" sufficient or should something more be
added?
If the stackless developers had considered a different license,
without changing the source or the license() output, that would
be pretty dumb.
Therefore, this question sounds strange to me, since either I am
dumb, or the question is obviously nonsense :-)
If you see an urgent need for further protection, please tell me.
I am more than happy with the Python license since 10+ years.
The Stackless addition is a concept, an idea. Europeans do not
consider patenting things like these.
The idea is obscene!
- chris
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