Hello I am trying to understand how servlet configuration and initialization parameters work and am running into a difficulty in Tomcat Version 4.1.18 I have the following configuration in in web.xml file -
<servlet> <servlet-name>StarChartServlet</servlet-name> <servlet-class>starchart.StarChartServlet</servlet-class> <init-param> <param-name>starChartWorkingDirectory</param-name> <param-value>C:\temp\</param-value> </init-param> </servlet> In the servlets init method, I have the following code: try { starChartWorkingDirectory = getServletConfig().getInitParameter("starChartWorkingDirectory"); } catch (java.lang.Exception ie) { System.out.println("Init Exception = " + ie.toString()); } and I am getting a null pointer exception thrown here... Nothing else appears to be wrong in the log files and the servlet does function except for this issue. Any help and guidance would be much appreciated! Thanks... Marc... --------------------------------------------------------------------- Do you think the software industry will ever make software that is as easy and reliable for a user to use as the automobile industry makes a car easy and reliable for a user to drive? ------------------------------------------------------------------------ A man said unto the universe - "Sir, I exist!" "However," replied the universe "I do not see where that creates in me a sense of an obligation." - Stephen Crane --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]