On Sun, May 12, 2019 at 8:05 AM Arup Rakshit <[email protected]> wrote:
>
> In the following the function, x is reachable outside the scope of foo
> function.
>
> In [1]: x = 10
>
> In [2]: def foo():
> ...: return x
> ...:
>
> In [3]: print(foo())
> 10
To what the others have said I wish to point out that if x is
reassigned _inside the function_ x's scope is now local inside the
function while x also still has a module scope. Consider:
3.6.8: x = 10
3.6.8: def foo():
... x = 5
... print("In foo x =", x)
...
3.6.8: foo()
In foo x = 5
3.6.8: print("In module scope, x =", x)
In module scope, x = 10
boB
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