2010/12/5 魏金仙 <sei_...@126.com> > If a particular client send 5 requests to a 6-node cluster, then the > probability of each node receiving(not be responsible for) the first request > is 1/6.
Assuming RF=1 and RandomPartitioner. > Assume that node1 received the 1st request, will node1 receive the 2nd > request, the 3rd one, the 4th one and the 5th one with high probability or > 1/6? > thanks for your time. > 1/6th with RandomPartitioner, something much higher with OrderPreservingPartitioner. -Brandon
