Just had another look at the class: in 2.13, the regex for matching
the encoding string was
Pattern.compile("<\\?xml.*encoding[\\s]*=[\\s]*((?:\".[^\"]*\")|(?:'.[^']*'))",
Pattern.MULTILINE);

In 2.14, the pattern includes the following matching for the encoding:
"encoding\\s*=\\s*((?:\"[A-Za-z]([A-Za-z0-9\\._]|-)*\")|(?:'[A-Za-z]([A-Za-z0-9\\\\._]|-)*'))",

This does not allow for an encoding that starts with a digit; i.e. it
won't match encoding='437'

AFAICT, no supported encodings start with a digit.

The '437' encoding is actually known as 'Cp437':
https://docs.oracle.com/javase/8/docs/technotes/guides/intl/encoding.doc.html
https://docs.oracle.com/en/java/javase/17/intl/supported-encodings.html

Try using 'Cp437' as the encoding.

On Tue, 3 Oct 2023 at 20:01, sebb <seb...@gmail.com> wrote:
>
> On Tue, 3 Oct 2023 at 18:05, Laurence Gonsalves
> <laure...@xenomachina.com> wrote:
> >
> > On Tue, Oct 3, 2023 at 1:39 AM sebb <seb...@gmail.com> wrote:
> > >
> > > The byte input stream does not carry any encoding information, so the
> > > XmlStreamReader has to guess what encoding was used.
> >
> > Determining what encoding to use when reading XML from a byte stream
> > is the purpose of XmlStreamReader. From its documentation: "Character
> > stream that handles all the necessary Voodoo to figure out the charset
> > encoding of the XML document within the stream."
> >
> > What it's supposed to do in this case is use the "encoding='437'" from
> > the input to determine that the Charset to use when decoding the byte
> > stream is "437" (aka "code page 437").
>
> Sorry, I completely overlooked that.
>
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