I think you need to specify new in single quote. My guess is the query
showing up in dB is like
...where status=new or
...where status="new"
Either case mysql assumes new is a column.
What you need is the form below
...where status='new'

You need to provide your quotes accordingly.

Easiest way would be to do it would in a separate jdbc conn to mysql using
a simple standalone programme, not in spark.
On 1 May 2015 07:47, "Burak Yavuz" <brk...@gmail.com> wrote:

> Is "new" a reserved word for MySQL?
>
> On Thu, Apr 30, 2015 at 2:41 PM, Francesco Bigarella <
> francesco.bigare...@gmail.com> wrote:
>
>> Do you know how I can check that? I googled a bit but couldn't find a
>> clear explanation about it. I also tried to use explain() but it doesn't
>> really help.
>> I still find unusual that I have this issue only for the equality
>> operator but not for the others.
>>
>> Thank you,
>> F
>>
>> On Wed, Apr 29, 2015 at 3:03 PM ayan guha <guha.a...@gmail.com> wrote:
>>
>>> Looks like you DF is based on a MySQL DB using jdbc, and error is thrown
>>> from mySQL. Can you see what SQL is finally getting fired in MySQL? Spark
>>> is pushing down the predicate to mysql so its not a spark problem perse
>>>
>>> On Wed, Apr 29, 2015 at 9:56 PM, Francesco Bigarella <
>>> francesco.bigare...@gmail.com> wrote:
>>>
>>>> Hi all,
>>>>
>>>> I was testing the DataFrame filter functionality and I found what I
>>>> think is a strange behaviour.
>>>> My dataframe testDF, obtained loading aMySQL table via jdbc, has the
>>>> following schema:
>>>> root
>>>>  | -- id: long (nullable = false)
>>>>  | -- title: string (nullable = true)
>>>>  | -- value: string (nullable = false)
>>>>  | -- status: string (nullable = false)
>>>>
>>>> What I want to do is filter my dataset to obtain all rows that have a
>>>> status = "new".
>>>>
>>>> scala> testDF.filter(testDF("id") === 1234).first()
>>>> works fine (also with the integer value within double quotes), however
>>>> if I try to use the same statement to filter on the status column (also
>>>> with changes in the syntax - see below), suddenly the program breaks.
>>>>
>>>> Any of the following
>>>> scala> testDF.filter(testDF("status") === "new")
>>>> scala> testDF.filter("status = 'new'")
>>>> scala> testDF.filter($"status" === "new")
>>>>
>>>> generates the error:
>>>>
>>>> INFO scheduler.DAGScheduler: Job 3 failed: runJob at
>>>> SparkPlan.scala:121, took 0.277907 s
>>>>
>>>> org.apache.spark.SparkException: Job aborted due to stage failure: Task
>>>> 0 in stage 3.0 failed 4 times, most recent failure: Lost task 0.3 in stage
>>>> 3.0 (TID 12, <node name>):
>>>> com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column
>>>> 'new' in 'where clause'
>>>>
>>>> at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
>>>> at
>>>> sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:57)
>>>> at
>>>> sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45)
>>>> at java.lang.reflect.Constructor.newInstance(Constructor.java:526)
>>>> at com.mysql.jdbc.Util.handleNewInstance(Util.java:411)
>>>> at com.mysql.jdbc.Util.getInstance(Util.java:386)
>>>> at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1052)
>>>> at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3597)
>>>> at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3529)
>>>> at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1990)
>>>> at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2151)
>>>> at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2625)
>>>> at
>>>> com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2119)
>>>> at
>>>> com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:2283)
>>>> at org.apache.spark.sql.jdbc.JDBCRDD$anon$1.<init>(JDBCRDD.scala:328)
>>>> at org.apache.spark.sql.jdbc.JDBCRDD.compute(JDBCRDD.scala:309)
>>>> at org.apache.spark.rdd.RDD.computeOrReadCheckpoint(RDD.scala:277)
>>>> at org.apache.spark.rdd.RDD.iterator(RDD.scala:244)
>>>> at
>>>> org.apache.spark.rdd.MapPartitionsRDD.compute(MapPartitionsRDD.scala:35)
>>>> at org.apache.spark.rdd.RDD.computeOrReadCheckpoint(RDD.scala:277)
>>>> at org.apache.spark.rdd.RDD.iterator(RDD.scala:244
>>>> at
>>>> org.apache.spark.rdd.MapPartitionsRDD.compute(MapPartitionsRDD.scala:35)
>>>> at org.apache.spark.rdd.RDD.computeOrReadCheckpoint(RDD.scala:277)
>>>> at org.apache.spark.rdd.RDD.iterator(RDD.scala:244)
>>>> at org.apache.spark.scheduler.ResultTask.runTask(ResultTask.scala:61)
>>>> at org.apache.spark.scheduler.Task.run(Task.scala:64)
>>>> at org.apache.spark.executor.Executor$TaskRunner.run(Executor.scala:203)
>>>> at
>>>> java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
>>>> at
>>>> java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
>>>> at java.lang.Thread.run(Thread.java:745)
>>>>
>>>> Does filter work only on columns of the integer type? What is the exact
>>>> behaviour of the filter function and what is the best way to handle the
>>>> query I am trying to execute?
>>>>
>>>> Thank you,
>>>> Francesco
>>>>
>>>>
>>>
>>>
>>> --
>>> Best Regards,
>>> Ayan Guha
>>>
>>
>

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