At 16:42 09/09/2017 +0000, Jonathon Kantoor wrote:
In the spreadsheet I'm working on, I'm trying to find the number of
items that are more than 6 standard deviations from the norm.
Standard deviation formula is StDev(Slant.B38:Slant.Slant.B1038)).
That formula works. The obvious solution, as expressed in the
formula COUNTIF(Slant.B38:Slant.B1038,>IQ_Slant.B44) does not work.
Error # 510: Missing Variable. Using quotation marks for the
criteria to search by (">IQ_Slant.B44") does not work. Is there a
way to count the number of cells whose value is greater than the
variable, when the variable is the value found in a specific cell?
Yup. Your syntax is almost right, but not quite. You need:
COUNTIF(Slant.B38:Slant.B1038;">"&IQ_Slant.B44)
You can no doubt see that COUNTIF() expects an inequality to be
expressed as a text string. So ">1234" will work, but not ">A1",
since that "A1" will not be seen as a cell reference. If you need to
incorporate a cell reference, you need to concatenate the ">" sign
with the value in the cell, which will automatically be converted to
text because of the context of the reference.
I trust this helps.
Brian Barker
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