Done, I had a lot of errors so I'll just show the final version that works OK.
=~ "192\.168\.([0-9]{1,3})\.([0-9]{1,3}) The only drawback is that I could pass as valid 192.168.999.999 but as these IPs come from a DNS query, I assume they'll be fine. Cheers, Uriel On Fri, Mar 26, 2010 at 11:29 AM, Uriel Rozenbaum <uriel.rozenb...@gmail.com > wrote: > Hi Alex, > > Actually what I'm trying to do is check the IPs on a request on a > Kamailio+RTPProxy acting as border of our network. > > So I have the ingress IP and egress IP and need to check if I have to > bridge ii, ei, ie or ee. > I managed to obtain all IPs in AVPs, but now I have to check if they are > public or private. > > So far our network uses only 192.168.x.x class for private servers. > > Thanks for the quick reply > Uriel > > > On Fri, Mar 26, 2010 at 10:56 AM, Alex Balashov <abalas...@evaristesys.com > > wrote: > >> 172.16.0.0/12 does not line up on octet boundaries. You will need to do >> something other than a regular expression. Fortunately, 'src_ip' is a >> composite that supports comparisons against subnets in shorthand CIDR >> notation. >> >> It might also be that whatever you are trying to accomplish can be done >> better some other way, but since you did not pose the question in terms of >> the objective, I cannot speak to that. >> >> -- >> Sent from mobile device >> >> >> On Mar 26, 2010, at 9:46 AM, Uriel Rozenbaum <uriel.rozenb...@gmail.com> >> wrote: >> >> Hi guys, >>> >>> Does anyone have a REGEX syntax to match a private IP on the 192.168.x.x >>> range? >>> >>> I'm trying with: >>> if($avp(s:ip_origen)=~"192.168(\.([1]?\d{1,2}|2[0-4]{1}\d{1}|25[0-5]{1})){2}" >>> ) >>> >>> But all IPs pass as private, even public ones. >>> >>> Thanks! >>> Uriel >>> _______________________________________________ >>> Kamailio (OpenSER) - Users mailing list >>> Users@lists.kamailio.org >>> http://lists.kamailio.org/cgi-bin/mailman/listinfo/users >>> http://lists.openser-project.org/cgi-bin/mailman/listinfo/users >>> >> >
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