Hello,
I found a solution for my problem that I'd like to share with you. Maybe it
helps others, too.
JBoss's ShrinkWrap Resolver makes it possible to run Maven embedded in your
code. I use it to run "help:effective-pom -Doutput=effective-pom.xml". Then I
read "effective-pom.xml" with MavenXpp3Reader that was mentioned by Karl Heinz
(thank you for that hint). This works only for poms that haven't a multi module
list. For poms with multi module list, the Maven Help Plugin creates a
effective-pom.xml with several <project> elements wrapped by a <projects>
element. This structure isn't known by MavenXpp3Reader.
The code snippet for that:
EmbeddedMaven.forProject("/path/to/pom.xml")
.addProperty("output", "effective-pom.xml")
.setGoals("help:effective-pom")
.build();
MavenXpp3Reader pomReader = new MavenXpp3Reader();
final Model pomModel = pomReader.read(new
FileInputStream("/path/to/effective-pom.xml"));
System.out.println(pomModel.getDistributionManagement().getDownloadUrl());
As dependencies, you need:
<properties>
<version.shrinkwrap.resolvers>3.0.0-beta-2</version.shrinkwrap.resolvers>
</properties>
<dependencies>
<dependency>
<groupId>org.jboss.shrinkwrap.resolver</groupId>
<artifactId>shrinkwrap-resolver-api-maven-embedded</artifactId>
<version>${version.shrinkwrap.resolvers}</version>
</dependency>
<dependency>
<groupId>org.jboss.shrinkwrap.resolver</groupId>
<artifactId>shrinkwrap-resolver-impl-maven-embedded</artifactId>
<version>${version.shrinkwrap.resolvers}</version>
</dependency>
<dependency>
<groupId>org.apache.maven</groupId>
<artifactId>maven-model</artifactId>
<version>3.5.0</version>
</dependency>
</dependencies>
Best regards,
Sandra
> Gesendet: Donnerstag, 10. August 2017 um 07:41 Uhr
> Von: spars...@web.de
> An: i...@soebes.de
> Cc: "Maven Users List" <users@maven.apache.org>
> Betreff: Aw: Re: How is the best way to get an effective POM outside of a
> Maven Plugin?
>
> Hi Karl Heinz,
>
> unfortunately, I need the full resolved pom.
>
> Best regards,
>
> Sandra Parsick
>
> > Gesendet: Mittwoch, 09. August 2017 um 19:24 Uhr
> > Von: "Karl Heinz Marbaise" <khmarba...@gmx.de>
> > An: "Maven Users List" <users@maven.apache.org>, spars...@web.de
> > Betreff: Re: How is the best way to get an effective POM outside of a Maven
> > Plugin?
> >
> > Hi Sandra,
> >
> > first question: Do you need the full resolved pom (effective pom) or
> > would it be enough just to simply to parse the pom file which can simply
> > being done using MavenXpp3Reader this would deliver the XML as a Maven
> > Model class which can simply being used to extract information from the
> > maven model...
> >
> > Kind regards
> > Karl Heinz Marbaise
> >
> > On 09/08/17 13:00, spars...@web.de wrote:
> > > Hello,
> > >
> > > currently, I'm working on a small tool, that needs some information of a
> > > POM and its parent POM. I didn't want to parse them with a XML reader, so
> > > I found that the DefaultModelBuilder can build a complete effective POM
> > > for me. Based on a stackoverflow answer
> > > (https://stackoverflow.com/questions/27383357/how-do-i-instantiate-mavenresolver-for-modelbuilder-usage)
> > > I build following example:
> > >
> > > DefaultModelBuilderFactory factory = new DefaultModelBuilderFactory();
> > > final DefaultModelBuilder defaultModelBuilder = factory.newInstance();
> > > ModelBuildingRequest buildRequest = new DefaultModelBuildingRequest();
> > > buildRequest.setPomFile(Paths.get("/path/to/a/pom.xml").toFile())
> > > .setProcessPlugins(false)
> > >
> > > .setValidationLevel(ModelBuildingRequest.VALIDATION_LEVEL_MINIMAL);
> > > final ModelBuildingResult modelBuildingResult =
> > > defaultModelBuilder.build(buildRequest);
> > >
> > >
> > > It works fine for simple POM (simple means a POM without a parent
> > > reference). But if I set a POM with a parent reference in
> > > buildRequest.setPomFile, I get following exception:
> > >
> > > Exception in thread "main" java.lang.IllegalArgumentException: no model
> > > resolver provided, cannot resolve parent POM groupId:artifactId:1 for POM
> > > groupId:artifactId:version (/path/to/a/pom.xml)
> > > at
> > > org.apache.maven.model.building.DefaultModelBuilder.readParentExternally(DefaultModelBuilder.java:890)
> > > at
> > > org.apache.maven.model.building.DefaultModelBuilder.readParent(DefaultModelBuilder.java:750)
> > > at
> > > org.apache.maven.model.building.DefaultModelBuilder.build(DefaultModelBuilder.java:309)
> > > at
> > > com.github.sparsick.maven.effecitve.pom.maven.model.builder.ApacheMavenModelBuilder.main(ApacheMavenModelBuilder.java:17)
> > >
> > > Another example on Stackoverflow
> > > (https://stackoverflow.com/questions/4838591/is-there-a-library-for-reading-maven2-3-pom-xml-files)
> > > mentions to use RepositoryModelResolver from Apache Archiva as an
> > > implementation ModelResolver. But I don't want to introduce a dependency
> > > to Apache Archiva in my tool.
> > >
> > > So my questions are, is the usage of DefaultModelBuilder the best way to
> > > get an effective POM of my project outside of a Maven Plugin? If so which
> > > implementation I should use for the ModelResolver? If not what is the
> > > best way to get the effective POM outside of a Maven Plugin.
> > >
> > > Thank you and best regards,
> > >
> > > Sandra Parsick
> > >
> > > ---------------------------------------------------------------------
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> > > For additional commands, e-mail: users-h...@maven.apache.org
> > >
> > >
> >
>
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