Hello,
I have come across this weird closure thing. In other programming languages, I would expect the closure in t to have a copy of i, but it only has a reference. Is it expected? Best regards, Vivien public delegate void Thunk(); public static void run (Thunk t) { t (); } int main() { int i = 0; Thunk t = () => { stdout.printf ("%d = 0, right?\n", i); }; i = 1; run (t); return 0; } _______________________________________________ vala-list mailing list vala-list@gnome.org https://mail.gnome.org/mailman/listinfo/vala-list