Hi,
I tried your example in my working environment. And in the web server's
output log,
I got the following error message:
2006-3-21 9:59:33 org.apache.catalina.core.ApplicationContext log
信息: Velocity [warn]
org.apache.velocity.runtime.exception.ReferenceException: reference :
template = /index.vm [line 8,column 1] : $\!foo is not a valid reference.
2006-3-21 9:59:33 org.apache.catalina.core.ApplicationContext log
信息: Velocity [warn]
org.apache.velocity.runtime.exception.ReferenceException: reference :
template = /index.vm [line 9,column 1] : $\!{foo} is not a valid reference.
2006-3-21 9:59:33 org.apache.catalina.core.ApplicationContext log
信息: Velocity [warn]
org.apache.velocity.runtime.exception.ReferenceException: reference :
template = /index.vm [line 10,column 1] : $\\!foo is not a valid reference.
2006-3-21 9:59:33 org.apache.catalina.core.ApplicationContext log
信息: Velocity [warn]
org.apache.velocity.runtime.exception.ReferenceException: reference :
template = /index.vm [line 11,column 1] : $\\\!foo is not a valid reference.
So I guess velocity engine regards the usage as an invalid usage.
Regards
吴耀华 写道:
>Advanced Issues: Escaping and !
>When a reference is silenced with the ! character and the ! character preceded
>by an \ escape character, the reference is handled in a special way. Note the
>differences between regular escaping, and the special case where \ precedes !
>follows it:
>
>#set( $foo = "bar" )
>$\!foo
>$\!{foo}
>$\\!foo
>$\\\!foo
>This renders as:
>
>$!foo
>$!{foo}
>$\!foo
>$\\!foo
>
>So that I can assume if i get a clause like:
>$\\\\\!foo
>that will render as:
>$\\\\!foo
>is it right? just lose one backslash?
>
>
>
>
>
>
>
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