You ask a very good and hard question. As an EE, I find much of Hotson's description much more satisfying that what I was taught in school. However, I wish Hotson was still around (now deceased) so that I could visit him to come to a greater understanding of his theory. He describes that the negative energy sea a is mass-less condensate of epos. When the epos form their DDL-like tiny orbits around each other, the Dirac solution for the orbit represents a "spinor field" that I find hard to grasp. In the spinor field, the particles have to orbit 720 degrees to get back to where they start. As the electron orbits the positron, the two switch roles part way around. Married together with his concept of discretezed time, the result is an orbit that looks more like two particles on the end of a string that just blink back and forth between being electrons and positrons. As part of this all, he has a description of the origin of inertial mass that I cannot entirely understand yet.
The net effect is that, yes, the inertial mass is used up in the dual photons of 511keV in transition to become epos, but that is not the total energy of the particles - they just gave up their inertial mass into energy. On Sun, Oct 25, 2015 at 7:01 PM, David Roberson <dlrober...@aol.com> wrote: > Bob > > Why does the electron charge to mass ratio come out in support of it > having 511 keV of energy if it really has much more? That seems > contradictory. The way I understand it, all of the energy has a mass > equivalent. > > Dave > > > -----Original Message----- > From: Bob Higgins <rj.bob.higg...@gmail.com> > To: vortex-l <vortex-l@eskimo.com> > Sent: Sun, Oct 25, 2015 3:05 pm > Subject: Re: [Vo]:slide deck for ultradense hydrogen / Leif Holmlid > > That is the energy given off to send the normal space positronium atom > into a DDL-like minimum energy orbit. When the electron-positron orbiting > pair becomes in the DDL orbit (orbital radius about the diameter of a > proton), it becomes undetectable and it is part of the negative energy > sea. It is still polarizable and it is the displacement of the epo sea > that provides electromagnetic "displacement". According to Hotson, the epo > (in the DDL orbit) has no inertial mass - for explanation of the origin of > mass you will have to read Hotson's papers. The epo sea IS the inertial > mass-less ether. > > Note that the 511keV is NOT the total energy of the electron. When the > spin energy of the electron is included, the total energy is over 16MeV. > The 1022keV (two photons of 511keV each) is the energy given up to > transition to the DDL state epo from the positronium atom. > > On Sun, Oct 25, 2015 at 12:19 PM, Eric Walker <eric.wal...@gmail.com> > wrote: > >> On Sun, Oct 25, 2015 at 12:56 PM, Bob Higgins <rj.bob.higg...@gmail.com> >> wrote: >> >> Regarding electrons and positrons in particular, Hotson rightly points >>> out that these two particles are fermions. As fermions, they are forbidden >>> to be in the same place at the same time, and so cannot annihilate. Instead >>> of annihilation, they fall into orbit around each other. When (if) they >>> reach a DDL orbit, the become a part of Dirac's negative energy sea. >>> >> >> If positrons and electrons do not annihilate, where do the two >> oppositely-travelling 511 keV photons come from as a result of the activity >> of beta plus emitters? (Note that 511 keV is the mass of an electron or >> positron.) >> >> Eric >> >> >
