Bob,

Now I see what you are suggesting and I agree with you 100%.   Two equal but 
opposite sources of angular momentum can combine together with a net of zero 
angular momentum, which is actually what existed mathematically in the closed 
system before they joined.  However, the rotational energy that each contains 
does not balance out when joined with its mate since energy is not a vector 
quantity.

I suppose that we can accept that nuclear energy can be released in a reaction 
which leads to the generation of two equal but opposite stores of angular 
momentum and the associated angular energy.  Each individual store of angular 
momentum can further be distributed to additional particles within the system.  
 At some future time these daughters might combine resulting in a pure release 
of energy with no residual angular momentum.

It seems likely that the final net release of energy could take place over an 
extended period of time.  This is pure speculation, but many of us seek a 
manner in which magnetic interactions can accept nuclear energy without needing 
to require a gamma release.  And, if it can be shown that the released energy 
interacts with a local magnetic field which causes it to build up in a positive 
feedback method that encourages the original nuclear reactions then all the 
better.

An electronic oscillator is an interesting analogue.  Noise of an extremely low 
level can be amplified by positive feedback until it saturates the oscillator 
device in one of these.

Dave

 

 

 

-----Original Message-----
From: Bob Cook <frobertc...@hotmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Tue, Mar 15, 2016 1:54 pm
Subject: [Vo]:Re: EM Drive(s)




Dave--
 
As I understand, the minimum spin quanta applies to transitions in all coherent 
systems.  I am suggesting that there may be a conversion of spin energy with 
its angular momentum to pure energy with no residual angular momentum.  That 
could be the case if two spinors with equal and opposite angular momentum were 
to come together to add pure energy to a system without associated angular 
momentum.  
 
Bob Cook 

 

From: David Roberson 
Sent: Tuesday, March 15, 2016 9:57 AM
To: vortex-l@eskimo.com 
Subject: Re: [Vo]:Re: EM Drive(s)

 
Bob,

I agree that It becomes difficult to relate to real life when one discusses 
rotational energy as you seem to imply.  In classical physical systems it is 
not too difficult to convert linear kinetic energy into rotational energy.  Of 
course the total closed system linear momentum and angular momentum need to be 
conserved separately and do not convert.

This is not to suggest that a linearly moving object could not impart angular 
momentum to a pair of rotating disks for example.  It just so happens that an 
equal and opposite amount of angular momentum is imparted to them such that the 
net sum is zero.  Some find this situation difficult to grasp.

Your concept about a minimum energy quanta is interesting but how would that be 
explained in the case of extremely low frequencies where the F approaches zero 
in the equation E=h*F?  Perhaps the spin quanta that follows your rule may only 
apply to atomic systems?

Dave

 
-----Original Message-----
From: Bob Cook <frobertc...@hotmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Tue, Mar 15, 2016 11:50 am
Subject: [Vo]:Re: EM Drive(s)




Dave—
 
People do not like to go there when it comes to the equivalence of spin angular 
momentum and other forms of energy.  Since spin has a minimum associated with 
the Planck constant, it suggests a minimum quanta of energy also IMHO.  I know 
of no explanation along these lines however.
 
Bob Cook

 

From: David Roberson 
Sent: Tuesday, March 15, 2016 7:33 AM
To: vortex-l@eskimo.com 
Subject: Re: [Vo]:Re: EM Drive(s)

 
Notice that I had an etc. at the end of that short list!  The poor guy ran into 
the wall as it was speeding in his direction.  It also happens that the Earth 
spins a little bit faster or perhaps slower than before the car's acceleration 
to absorb some of that original energy.  It can get complicated very quickly if 
we add considerations of rotational energy to the discussion.  I'd rather not 
go there.

Dave

 
 
 
-----Original Message-----
From: mixent <mix...@bigpond.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Tue, Mar 15, 2016 12:07 am
Subject: Re: [Vo]:Re: EM Drive(s)

In reply to David Roberson's message of Mon, 14 Mar 2016 20:56:31 -0400:
Hi,
[snip]
>Trick question. All of the energy used by the electric drive could be 
>accounted for from the frame of the car by observing frictional losses, wind 
>movement, heat emissions, etc. It would not be easy to calculate, but the 
>information should be there.
>
>Dave

Try convincing the driver, that is now in hospital because he drove into a
concrete wall at high speed, that all of the stored energy was lost to wind
resistance and road friction. 

Regards,

Robin van Spaandonk

http://rvanspaa.freehostia.com/project.html







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