Oops a bit dyslexic – the 2:1 ratio is between deuterium and titanium – TiD2 and not the other way around... every atom of titanium binds two deuterons…
--------------- Another interesting detail is the ratio of titanium to deuterium. This is the so-called loading ratio. In cold fusion, the goal is to reach 1:1 ratio of palladium to deuterium and this ratio is difficult to achieve and a main reason for failed results. In contrast all titanium hydride will have a natural loading ratio of 2:1 at the very least and a 3:1 ratio is possible. The reason for this difference is found in the complexity of “covalency”. The bond is much more energetic in titanium - which can be a problem in itself. The covalency of titanium and the high natural loading is not an advantage for electrolysis since it changes the electrical conductivity too much - but would be a big advantage for a Coulomb explosion system. The Coulomb explosion is the key and this means that a laser will probably be the only way to trigger the fusion reaction reliably. Terry, It looks like the uncompressed hydride TiD2 has a density of 3.9 g/cm3 The pure Ti metal has a density of 4.5 g/cm3 The normal hydride which has not been compressed contains 4% hydrogen but as a result is reduced in density by 13% Adding hydrogen as a hydride would normally be counterproductive when the goal of facilitating fusion is to increase particle density, unless the hydrogen (deuterium) were absorbed deeply into the Titanium atom orbital. If the deuterium is completely absorbed, then the density of the hydride would be no more than 4.6 g/cm3 or hardly noticeable but the end result would be deuterons which are much closer together and presumably easier to fuse due to proximity. The Lawson criteria would be vastly enhanced with absorbed deuterons. https://en.wikipedia.org/wiki/Lawson_criterion From: Terry Blanton Interesting characteristics: • Density 3.9 G/cm3 • Composition Ti - 95.95, H - 4.05
