At 05:19 PM 12/22/2009, mix...@bigpond.com wrote:
In reply to Abd ul-Rahman Lomax's message of Fri, 11 Dec 2009 10:29:37 -0500:
>Some of the alphas,
>statistically, would be hot enough to induce secondary reactions as
>well. (Which comes first, the photon emissions or the fission?)
[snip]
Be8 has a very short half life. I would expect
an excited state to have an even
shorter half-life (a lot shorter). Therefore I
would expect the fission to occur
first. However perhaps energy is radiated from the complex while it is
shrinking?
I don't think so, as to radiation while
condensing. However, Takahashi has covered the
expected radiation after fusion, in an earlier
publication. First, though, looking for the
earlier paper, I'll quote this as an explanation
of the process, from a 2007 paper.
http://www.newenergytimes.com/v2/library/2007/2007TakahashiA-TheoreticalSummary.pdf
In Fig. 3, TSC will form in the near surface
region of condensed matter by the mechanism (A) or mechanism (B)
as discussed in Session 2, with certain
probability depending on methods of experiments and near-surface physics of
condensed matter: Step 1 (TSC forms). Then TSC
starts Newtonian squeezing motion to decrease linearly its size from
about 100 pm radius size to much smaller size and
reaches at the minimum size state: Step 2 (minimum TSC). Classical
squeezing motion ends when four deuterons get
into the strong force range (5 fm) and/or when four electrons get to the
Paulis limit (about 5.6 fm for ee distance).
Here for the Paulis limit, we used the classical electron radius of 2.8 fm,
which is determined by equating the static
Coulomb energy (e2/Re) and the Einsteins mass energy (mec2) to obtain
Re = e2/mec2 = 2.8 fm; classical electron radius. (16)
Since the range of strong interaction (about 5
fm) is comparable to the classical electron diameter (5.6 fm), as shown
in Fig.3(2), the intermediate nuclear compound
state 8Be* will be formed just after the minimum size state (overminimum
state); Step 3: 8Be* formation. Immediately at
this stage, 4d-cluster shrinks to much smaller size (about
2.4 fm radius) of 8Be* nucleus, and four
electrons should go outside due to the Paulis repulsion for fermions. Shortly
in about few fs or less (note; Lifetime of 8Be at
ground state is 0.67 fs), 8Be* will break up to two 4He particles, each
of which carries 23.8 MeV kinetic energy; Step 4:
Break up. It will take about 60 fs from about 100 pm initial size of
TSC to its minimum size about 10 fm. About 60 fs
is regarded as rough measure of TSC lifetime for this very transient
squeezing motion.
Takahashi gives very strong arguments as to why
the hypothesis of direct d-d fusion to He-4 is implausible.
In any case, I found the page I'd seen where I
got the idea that Takahashi is proposing loss of
Be-8 excitation energy through photons. His more
recent papers, as far as I saw, don't mention
this, but I don't see a discussion, either, of
the rejection of the idea. However,
http://www.lenr-canr.org/acrobat/TakahashiAdeuteronst.pdf,
a presentation from ICCF 13 (2007), has a copy of
a diagram from his earlier paper, which is from
Fusion Technology (1994), see page 36 of the linked paper.
In the "extreme scenario," the final products are
two alpha particles with 46.6 keV each, and "most
energy (47.7 MeV) is transferred to lattice
vibration via QED photons." He then predicts a
series of energies will be found, ranging from
the minimum all the way up to the full 23.8 MeV
that would be expected to result from immediate decay.
And he states, after this, that "quantitative
studies on transition probabilities will be needed."
Apparently Takahashi thinks, contrary to what
Robin suggests, that photon emissions are
possible in the lifetime of the Be-8 nucleus,
before it breaks up. He does not predict the
ratios, only the values expected for He-4 energies.
