Good grief Jed! You have to keep straight the difference between mass
and volume!
Your reference clearly states "If the water content of the steam is
5% by mass, then the steam is said to be 95% dry and has a dryness
fraction of 0.95."
By my table, 95% steam has way less than 0.1% water by volume. This
would barely make any difference in capacitance.
Also note that your refer to 5 bar steam. That has 5 times the mass
in vapor as atmospheric steam. I'd do some calculations regarding
this, but just don't have time. I don't even have time to read all
the vortex posts right now.
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
On Jan 23, 2011, at 6:23 AM, Jed Rothwell wrote:
Horace Heffner <[email protected]> wrote:
We can thus see from this table that if 1 percent by volume of the
steam is entrained water micro-droplets, easily not seen in tubing
or exhaust ports, that only 5.6 percent of the heat of vaporization
is required to produce that mixture.
I do not think so. See:
http://www.engineeringtoolbox.com/wet-steam-quality-d_426.html
QUOTE:
Example - Enthalpy and Specific Volume of Wet Steam
Steam at pressure 5 bar gauge has a dryness fraction of 0.95.
Total enthalpy can be expressed as:
ht = (2085 kJ/kg) 0.95 + (1 - 0.95) (670.4 kJ/kg)
= 2,014 kJ/kg
Specific volume can be expressed as:
v = (0.315 m3/kg) 0.95
= 0.299 m3/kg
That says 2,014 kJ/kg (not 2.0). Almost as much enthalpy as dry steam.
Anyway, we can test this at home. Get something like an electric
frying pan, rated at 1.5 kW. Boil some water in. That produces wet
steam; you can see the vapor condensing about the pan. The power is
half of the 2.97 kW Heffner estimates the Rossi device may be
producing (assuming 1% wet steam). So, it should be able to boil
away the water in about twice the time it takes Rossi. Take a
gallon of water (3.8 L) starting at 15 deg C, and see if you can
boil away the entire gallon in 26 minutes.
- Jed
