On Mon, Feb 21, 2011 at 11:52 AM, Horace Heffner <hheff...@mtaonline.net>wrote:
> > On Feb 21, 2011, at 5:50 AM, Joshua Cude wrote: > > One should also bear in mind that it takes only 2% steam by mass to make >> up 97.5% of the expelled fluid by volume. And since the steam is created in >> the horizontal portion, it is forced up 50 cm of pipe through liquid, which >> would presumably turn the liquid into a fine mist after a few minutes. >> > > > The above appears to to be a typo. It was probably meant to say: "One > should also bear in mind that it takes only 2% steam by *volume* to make up > 97.5% of the expelled fluid by *mass*. Well maybe a question of semantics, and some rounding errors. Try this: It takes only 2% of the H2O by mass, in the form of steam, to make up 97% of the expelled water by volume. For an input flow rate of 300 cc/min = 300 mg/min, 2% of the water by mass means .02* 300 = 6 mg water per minute in the form of steam. The density of steam at 1 bar is .59 micrograms/cc, so that amounts to 10,000 cc/minute steam. The remaining liquid, 294 mg/ min = 294 cc/min, therefore makes up 2.8% of the volume.
