Explaining Rossi.
Rossi said: “We think that all the Ni participates to the reactions, even if some isotopes should be more efficient.” “Only Ni 62 and Ni64 react.” Rossi enriches his nickel in Ni62 and Ni64. Why? Through experimentation, Rossi found these isotopes performed best. But what is the theory behind this result? Nickel-62 is an isotope of nickel having 28 protons and 34 neutrons. It is a stable isotope, with the highest binding energy per nucleon of any known nuclide (8.7945 MeV). The high binding energy of nickel isotopes in general makes nickel an "end product" of many nuclear reactions (including neutron capture reactions) throughout the universe and accounts for the high relative abundance of nickel and nickel-60 (the second-most, with the other stable isotopes (nickel-61, nickel-62, and nickel-64) being quite rare). Nickel is the least likely element to participate in a fusion reaction. If atomic holes are the place where the Rossi reaction occurs, Rossi wants a very strong and stable support structure that can provide a three dimensional quantum box that can produce the reaction. Under the assumption that only hydrogen reacts in the quantum box and that many hydrogen atoms are fused in the Rossi reaction; the packing of all those hydrogen atoms into the lattice defects of nickel is a stressful process. If this nickel built Heisenberg box were to fail or fail apart during the packing of hydrogen, then the reaction will fail. Nickel is the most stable element because its binding energy is maximized among the elements. The nickel isotopes that are the most stable are Ni62 and Ni64. Rossi enriches his nickel in these most stable and stout isotopes because they can best support the atomic defects he uses to produce atomic events without blowing the lattice defects apart during the stresses of the atomic reactions and were nickel garbage would poison the pure hydrogen reaction. Elements on either side of nickel will perform best because of their very high binding energies.
