http://en.wikipedia.org/wiki/Aneutronic_fusion

This wiki site has some info on ‘wishful’ and desirable, but well-known
fusion reactions, including the one which is (by far) the most interesting
to everyone who has looked into this - and the most studied:

p + 11B → 3  4He +  8.7 MeV

This reaction is cleaner than clean, in nuclear terms. No residual
radioactivity and no neutrons. Alphas do not go very far. Now imagine that
the proton is not really a proton at all, until it enters the nucleus, but
is essentially neutral. 

In fact it is monatomic hydrogen (spillover) in which the electron has
become trapped in a low orbital (or else the Mills’ hydrino or a proton
with a deflated electron) and thus appears charge-neutral when approaching a
boron nucleus at low energy. 

Nickel can do that kind of electron magic, according to Randell Mills and
many others. The term “virtual neutron” has been used for this particular
species. It can easily go through solid metal walls, just like a neutron,
and it moves from the nickel side of a wall to the boron side, with ease,
like a neutron. But boron has a high affinity and it can go no further.

However, it still needs energy to tunnel into the boron nucleus - which, in
QM terms, is “borrowed in advance” from the large amount available in the
end. This makes it true LENR, not hot fusion. It is the best of both worlds.

Falsifiability. Two details (findings) would seal-the-deal for this reaction
being the Rossi effect
1)      Finding helium with the boron, but not with the nickel
2)      Proving that the reaction can happen without a gamma signature above
200 keV
                
The last one is the hardest, of course.

Jones

____________________________________________

In the case of boron-10 reacting with a virtual neutron, this would be
closer to fission than fusion, if we wanted to be precise - and also is
lower in energy than the reaction of boron with a real neutron (which is
over 1 MeV heavier than a proton). If the “virtual neutron” is a form of
spillover with a deflated electron, or a maxed-out hydino, then the reactive
particle could be lower in mass yet.

This is getting somewhere … but … Can such a reaction be hidden from
sophisticated gamma detection, that is the question? … i.e. for whether or
not this could be applicable to the Rossi effect.

On the plus side - the ash might be helium and lithium-6 (instead of
lithium-7) and the gain is more evenly split between the two. The crux of
the situation is that if the boron layer (of an E-Cat reactor) is ever
tested for isotopes (NOT the nickel itself) and helium is indeed found in
the boron, then “boron fission” becomes a prime candidate for gain instead
of nickel transmutation. There would be no residual radioactivity expected
in boron fission.

BTW the appearance of the E-Cats is distinguished by black gunk - which
could be a result of the flux used to braze the tubes … OR … possibly
related to leakage of boron during fabrication, which is black in coloration
and often comes mixed with carbon anyway. 

One final note (even further afield) is that The Boron-10 isotope is
excellent for capturing thermal neutrons but only about 20% of the natural
element. 80% is 11-B. 

The worldwide nuclear industry routinely enriches natural boron to nearly
pure 10-B, and the less-valuable by-product, depleted boron, is almost a
giveaway item … but a hack inventor might not appreciate this, if he were
not trained in nuclear physics. And … if he were the luckiest man on earth
:-) which would be the case if the “virtual neutron” were discovered to
work especially well with 11-B, instead of 10-B; then the yield could be 3
alphas. Three alphas, when forming at low net enthalpy - could be in the
range where secondary bremsstrahlung would be completely hidden from view
(way under 200 keV) but that is far from clear…. 

… worth mentioning, however, since it will give Robin a nice segue to
expound on how a hydrino + 11-B could be the ideal kind of nuclear reaction
- which would escape gamma detection for the most part, and yet have a good
yield with no residual radioactivity and no other indicia either. 

Geeze, it is almost a “designer reaction” … but that does not improve the
long odds …

Jones



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