[This was sent directly to Milstone by accident, because of the way his
e-mail response is set up. This happens at Vortex from time to time.]
John Milstone <john_sw_orla...@yahoo.com
<mailto:john_sw_orla...@yahoo.com>> wrote:
From the report:
"The three-phase power cables were checked and connected directly to
the electrical outlet. It was established and verified that no other
cable was present and that all connections were normal. The ground
cable was disconnected before measurements began."
It’s clear that the authors of the report were using the term
“cable” to refer to a single, insulated wire. They were looking for
extra wires. Nothing in their description even suggests that they
were looking for extra conductors in a single wire.
This is incorrect. They mean "wire" here, not the whole insulated cable.
We know this because:
1. The only way to measure voltage is to expose the bare wire and attach
a probe to it, as shown in Fig. 1. It is NOT POSSIBLE to measure
voltage any other way.
2. If there were two conductors separately insulated and hidden the
researchers would surely notice this when they open the wire to attach
the voltmeter. Or if they did not notice it, the two wires now exposed
would short out after the researchers cut the insulation.
3. In an insulated electric 3-phase cable, all four wires are bundled
together under the insulation. The ground wire is not individually
broken out, so you cannot "disconnect" it, as they did here. The only
way to disconnect it is to cut off the outer insulation and expose the
individual wires. (You also have to check the voltage to make sure you
have disconnected ground.)
The device in the photos is a tube containing Rossi’s magic gadget
AND conventional electrical resistance heaters. There is no way to
prove that the heat being radiated from the surface came from the
E-Cat and not the electric heaters.
The heat from the e-Cat has to come from both. It is not possible to
isolate a source of heat when two are present. Heat is heat, and it is
indistinguishable whether it comes from an electric heater, friction, a
flame, or a nuclear reaction.
However, in this case we know exactly how much heat is added to the
system by the electric input power: 300 W. This can be measured with
high precision and absolute confidence. We know that 900 W is coming
out. Therefore, 600 W must be anomalous heat.
This is how all calorimeters work. No calorimeter can distinguish the
source of heat. When there are two sources of heat in a reactor, the
calorimeter can never tell you how much heat each one is contributing
_unless_ you have a method of measuring input to one of the sources. In
this case, we have that.
- Jed
