|
Hi Nirmal,
Thanks for the information.
I
manually changed the WSDL soap:address at the moment but, I'll use this
to programmatically change it.
This is very useful. I'll try this
later.
Again thanks.
Leo
----- Original Message -----
Sent: Thursday, November 06, 2003
2:18 AM
Subject: Re: Service Name's
soap:address location
Hi,
You can modify the service endpoint in
the WSDL definition programmatically. Here is some sample code which should do
this (not compiled or tested, but it should be approximately correct). This
uses the standard WSDL API being defined in JSR110 (see http://oss.software.ibm.com/developerworks/projects/wsdl4j
for the reference implementation).
WSDLFactory factory = WSDLFactory.newInstance();
WSDLReader reader = factory.newWSDLReader();
Definition def =
reader.readWSDL(null,"sample.wsdl");
Service service = def.getService(new QName("foo","bar"); // accesses
service named foo:bar
List extElements
= service.getExtensibilityElements();
SOAPAddress address = (SOAPAddress) extElements.get(0); // this assumes
that there is only one extensibility element under <service>, viz.
soap:address
address.setLocationURL("http://newURI");
Now the definition (def) can be used by WSIF to create
a WSIFService that will attempt to invoke the service whose SOAP endpoint is
http://newURI.
Hope that
helps,
Nirmal.
|
| "David Seager"
<[EMAIL PROTECTED]>
10/30/2003 08:13 AM
Please respond to wsif-user
|
To:
[EMAIL PROTECTED]
cc:
Subject: Re: Service Name's
soap:address location |
Hi Leo,
That WSDL shouldn't execute correctly from a
remote client, as localhost
will resolve to the machine it's being run on.
The best way is to store the
WSDL on a web server on the remote server
machine, with the location set
with the remote server's hostname. Then
point the client at the WSDL on the
remote server.
However, if you
know which provider gets used, there are methods on some to
override the
location URL. In the WSIFPort_ApacheAxis class, in the Apache
Axis
provider, there is a setEndPoint method which will do the trick. Here
is my
code which changes the URL to something else:
String wsdlLocation =
"http://localhost:8080/axis/Expire.jws?wsdl";
WSIFServiceFactory factory = WSIFServiceFactory.newInstance();
WSIFService service = factory.getService(wsdlLocation, null,
null,
null, null);
WSIFPort p =
service.getPort();
// override port
WSIFPort_ApacheAxis pA = (WSIFPort_ApacheAxis)p;
pA.setEndPoint(new
URL("http://localhost:8081/axis/Expire.jws"));
o =
p.createOperation(operation);
m1 =
o.createInputMessage();
m2 =
o.createOutputMessage();
m3 =
o.createFaultMessage();
boolean ok =
o.executeRequestResponseOperation(m1, m2, m3);
The WSDL referenced
defines the Expire service to be at
http://localhost:8080/axis/Expire.jws.
However, the above code sends the
request to the address in the override
call. This only works if the
provider being used is Apache
Axis.
Regards,
David Seager
IBM Hursley
Internet
[EMAIL PROTECTED]
"Leo Barcenas"
<[EMAIL PROTECTED] To:
<[EMAIL PROTECTED]>
>
cc:
Subject:
Service Name's soap:address location
30/10/2003 11:33
Please respond
to
wsif-user
Hello!
I would like to ask about the
WSDL file used in WSIF. In particular,
the soap:address location of the
Service name.
I'm just quiet puzzled that some of the files I saw is
written the one
below,
<service
name="ServiceNM">
<port name="SoapPort"
binding="tns:SoapBinding">
<soap:address
location="http://localhost/WSDL/iLON100.WSDL" />
</port>
</service>
Considering the above
WSDL syntax, will this be able to correctly execute
from a remote client?
If not, is there a way that you can change
"localhost"
into the IP
address of the server where the web service is located during
runtime? I've
tried it in VB.NET by using the WebReference's URL property
and replacing
"localhost" to the server's IP address.
Hoping for your
answer.
Many
thanks.
Leo
|
