> EvdevBitIsSet(array, KEY_A): array[0] & (1 << 30) > BitIsOn(ptr, KEY_A): ((BYTE*)ptr)[3] & (1 << 6) That is true on little-endian. Big-endian machines have that byte in position 0, so that one would need to be ((BYTE*)ptr)[0] & (1 << 6).
Another simpler example: long a = 0x04030201; Big-endian: ((unsigned char*)&a)[0] == 0x04 ((unsigned char*)&a)[1] == 0x03 ((unsigned char*)&a)[2] == 0x02 ((unsigned char*)&a)[3] == 0x01 It's weird because we're used to developing on little-endian ;-) AFAIK the fact that casting to shorter types "just works" is one of the reasons why little-endian is used everywhere. This wouldn't be a problem if we exclusively used SetBit/BitIsOn everywhere. But we get the bitmask from the kernel, which uses longs and uses correct byte order... Max _______________________________________________ xorg-devel@lists.x.org: X.Org development Archives: http://lists.x.org/archives/xorg-devel Info: http://lists.x.org/mailman/listinfo/xorg-devel
