Hi All,
I am reading the SF0-02 version which is just released few days ago.
In the SF0 Allocation Policy section, the policy said
1. If REQUIREDCELLS<(SCHEDULEDCELLS-SF0THRESH), delete one or more
cells.
2. If (SCHEDULEDCELLS-SF0THRESH)<=REQUIREDCELLS<=SCHEDULEDCELLS, do
nothing.
3. If SCHEDULEDCELLS<=REQUIREDCELLS, add one or more cells.
Personally thinking, add/delete one cells may call the sixtop many times
which is not efficiency, add/delete more cells is not clear to the
implementer.
I guess there is a decision to say when to add one cell and when to add
more cells. But I didn't find it in SF0 draft.
Is there any reason why we doesn't say specific number of cells?
If no, I think we can add/remove the number of cells to make sure the
scheduled cells equals to the required cells plus half of SF0THRESH, which
will help stabilize a little bit of the SF0, in case the sixtop is calling
too often.
Which means: if SCHEDULEDCELLS<=REQUIREDCELLS:
1. when there is no cell in the schedule add one cell
2. when there is at least one cell in schedule, add
REQUIREDCELLS-SCHEDULEDCELLS+(SF0THRESH+1)/2 number of cells
if REQUIREDCELLS<(SCHEDULEDCELLS-SF0THRESH))
1. When required cells equals 0, remove all cells but keep one in schedule
2. when required cells is greater than 0, remove SCHEDULEDCELLS-
REQUIREDCELLS-(SF0THRESH+1)/2
Does this make sense?
Tengfei
--
Chang Tengfei,
Pre-Postdoctoral Research Engineer, Inria
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