I've been trying to figure out this little one for a while now and figure I
could use a refresher course in regexp.
There are quite a few files that I'm trying to copy through grap that would be
really easy if I could take a line like:
# (Yo 4.9534)
and turn it into a value for x,y graphing. Unfortunately, I'm completely
blanking out on how to get that pesky ')' stripped out. I try the following:
if "$2" == "(Yo" then {
print sprintf("Yo was %f", yo)
yo = sh { echo $3 | sed 's/\)#//' }
print sprintf("Yo is %f", yo)
}
but that just gives me:
cpu% eval `{doctype t.g} | lp -dstdout > t.ps
Yo was 8.579000
rc: line 2: token ')': syntax error
grap: syntax error???: No such file or directory
near 20100809_pscheck_XX.d:8
context is
yo = sh { echo 4.9534)# | sed 's/\)#//' } >>> <<<
I'm not quite sure why grap converts $3 into "4.9534)#", so I try brute force:
cpu% echo '4.9534)#' | sed 's/\)#//'
4.9534
Does anyone have any hints on what might I be doing wrong in my grap source?
-jas
