i doesn't exist -- it was optimized away because your code is equivalent to this
void
m00(...)
{
int i;
if(foo){
for(i = 0; i <= n; i++){
some_data[i] = srcdata[i]
}
} else {
...
}
}
because i == j.
- erik
On Sat Jul 15 05:55:56 CDT 2006, [EMAIL PROTECTED] wrote:
>
> Hi folks,
>
> I got a function which goes like this:
> void
> m00(...)
> {
> int i,j = 0;
>
> if(foo) {
>
> for(i=0;i<=n;i++) {
> some_data[j++] = srcdata[i]
> }
>
> } else {
> ...
> }
> }
>
> (ignore the errors)
>
> I get a fault write. Jippie. Starting to acid arround, I came across this:
>
> acid: *m00:j
> 0x00000000
> acid: *m00:i
> <stdin>:3: (error) colon: local variable not found
> acid:
>
> so obviously acid does not 'see' i because it is first used in a new block
> (the if()), at least I guess so. How do I display the value of i in acid?
>
>
> Mfg, Sascha
