Hello,
I am exploring the tools on Plan 9 and I am having a problem
getting the correct files to be included. My test setup is
that I have a directory with C source and headers. In a sub-
directory, I have the plan 9 mkfile and a customized version
of one of the header files. I would like the C compiler to
find my customized version of the header instead of the one
in the original source directory.
The desired results of running my test is:
cpu% cd source/plan9
cpu% mk
cpu% ./main
MSG = this is from plan9/inc1.h
MSG2 = this is from inc2.h
cpu%
However, everything I have tried results in:
cpu% ./main
MSG = this is from inc1.h
MSG2 = this is from inc2.h
cpu%
The files I am using for the test are:
source/
inc1.h
inc2.h
main.c
plan9/
inc1.h
mkfile
inc1.h:
#define MSG "this is from inc1.h"
inc2.h:
#define MSG2 "this is from inc2.h"
main.c:
#include <u.h>
#include <libc.h>
#include "inc1.h"
#include "inc2.h"
void
main (int argc, char *argv[])
{
print ("MSG = %s\n", MSG);
print ("MSG2 = %s\n", MSG2);
exits (0);
}
plan9/inc1.h:
#define MSG "this is from plan9/inc1.h"
plan9/mkfile
</$objtype/mkfile
CFLAGS=-p -N -.
LDFLAGS=
main: main.$O
$LD $LDFLAGS -o main main.$O
main.$O: ../main.c
$CC $CFLAGS ../main.c
clean:V:
rm -f main main.$O
I have tried many combinations of -N, -., -I., -I.., and nothing
seems to work. I would expect that the above CFLAGS definition
would cause the compiler to not find either inc1.h or inc2.h.
However, even with CFLAGS=-p -N -., it finds both the header files
in source.
If I do not use the ANSI preprocessor, setting CFLAGS=-. -I. -I..
works.
I am running on a Plan 9 cpu server that I updated on May 18.
Any enlightenment would be appreciated.
Kim
