On 19 Mar 2001 12:57:29 +0000, [EMAIL PROTECTED] wrote:
> On Mon, Mar 19, 2001 at 01:48:31PM +0100, Joaquin Cuenca Abela wrote:
> > On 19 Mar 2001 14:04:57 +0400, Vlad Harchev wrote:
> > > Then the following could be used to multiply 'x' by 1.5:
> > >       (x + x<<1) >> 1
> > > I will be very fast.
> > uhm, it's not so readable as x = x * 1.5.  In addition, if later we
> > decide to change from 1.5 to something else, it becomes harder.  And
in
> 
> Can we have a sort of middle point here?
> 
> x = x * y should be replaced by x *= y

The real line is:

n = priv_max(n, nCurSize * g_nGrowBy);

Cheers,

-- 
Joaquín Cuenca Abela
[EMAIL PROTECTED]


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