If you know the formula for the compound interest, take the present
population as the principal and solve it.
I am writing the formula for the same.
Principal * (1+ rate /100) ^N times
Putting this formula and substituting the numbers:
1,50,000 (105/100) ^2 = 165375. This is the answer of the first part.
Now the second part is: What was the population two years back.
For this:
150000 (100/105) ^ 2 =
136054.4
Now the second question.
Suppose, the total number of students is 100.
20 failed in both subjects. therefore, subtract the amount from the
total numbers = 100 = 80.
Now, 35 minus 20 = 5 students failed in Hindi only.
Therefore, 80 minus 5 = 75 % students passed in Hindi.
And
80 minus 15 = 65 % students passed in English.
----- Original Message -----
From: "Mohib Anwar Rafel" <mohibra...@gmail.com>
To: "accessindia" <accessindia@accessindia.org.in>
Sent: Saturday, June 22, 2013 9:34 PM
Subject: [AI] help me in understanding the method for solving such type of
mathematical problems
Hi friends I am unable to understand the way to solve the following
problems, even I couldn't understand it by reading R. S. Agarwal book.
please guide me.
1. If the population of a town is 1,50,000 at present, it is
increasing at the rate of 5% per annum,
(a) what will be the population of the town after 2 years?
(b) what was the population of the town before 2 years?
2. In a class 35% students failed in hindi, 45% failed in english
subjects respectively. 20% students failed in both subjects, find out
the percentage of the students who passed in both subjects.
--
Mohib Anwar Rafel
M.Phil/Masters in International Law, Center for International Legal
Studies JNU.
Pursuing Masters of Law, at University of Delhi
Phone: 09811767506,
01127666896
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