[EMAIL PROTECTED] wrote:
>> (by default, 'time()' is the param for localtime() ). So you can
>> get the values for yest by subtracting 1 day worth of seconds:
>> my ($mday, $mon, $year) = (localtime(time() - 60 * 60 * 24) ) [ 3,4,5];
>> printf("%d/%02d/%02d\n", $year + 1900, $mon + 1, $mday - 1);
Will there be a time when that's wrong due to daylight saving time changes?
--
Henry
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