On Dec 3, 2008, at 8:34 , Henry Hartley wrote:
> [EMAIL PROTECTED] wrote:
>
>>> (by default, 'time()' is the param for localtime() ). So you can
>>> get the values for yest by subtracting 1 day worth of seconds:
>>> my ($mday, $mon, $year) = (localtime(time() - 60 * 60 * 24) )
>>> [ 3,4,5];
>>> printf("%d/%02d/%02d\n", $year + 1900, $mon + 1, $mday - 1);
>
> Will there be a time when that's wrong due to daylight saving time
> changes?
Yes. There are 2 hours each year when this formula is wrong.
--Gisle
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