Hello everybody, The MSDN says about ShowDialog that
"When a form is displayed as a modal dialog box, clicking the Close button (the button with an X at the upper-right corner of the form) causes the form to be hidden and the DialogResult property to be set to DialogResult.Cancel. Unlike modeless forms, the Close method is not called by the .NET Framework when the user clicks the close form button of a dialog box or sets the value of the DialogResult property. Instead the form is hidden and can be shown again without creating a new instance of the dialog box. Because a form displayed as a dialog box is not closed, you must call the Dispose method of the form when the form is no longer needed by your application." The way I understand this is that even if I re-instantiate the class that implements my form, the framework will reuse some previously created structures and that's how I would explain why the Load event is not fired for subsequent calls to ShowDialog. So here is my question: What is the pattern I need to use to display one form over and over and make sure that all internal controls are initialized to proper values every time the form is shown? What is the event that's fired every time ShowDialog is called, if there is such an event? If not, how else should I approach this? TIA, Eddie =================================== This list is hosted by DevelopMentorĀ® http://www.develop.com View archives and manage your subscription(s) at http://discuss.develop.com