Hi Geoff, It's been suggested before, your solution, but I thought there would be another way. Not that there is anything wrong with your idea. Anyway, I implemented it and it is working. Thanks, Eddie
-----Original Message----- From: Discussion of advanced .NET topics. [mailto:[EMAIL PROTECTED] Behalf Of Geoff Taylor Sent: Monday, November 27, 2006 10:47 AM To: ADVANCED-DOTNET@DISCUSS.DEVELOP.COM Subject: Re: [ADVANCED-DOTNET] Events fired when Form.ShowDialog is called How about: using (MyDialog dialog = new MyDialog ()) { // Call your initialise method dialog.MyInitialise (); if (dialog.ShowDialog () == DialogResult.OK) { // Fetch my results results = dialog.GetMyResults (); } } So, you can add whatever initialisation you need in your MyInitialise () method, and get whatever values you need from your GetMyResults () method. The 'using' statement will handle the Disposal automatically, and you're instantiating a new MyDialog each time through the code so you shouldn't have any problems with re-using an existing object. As for the event that's fired every time ShowDialog is called, the only way I've found of doing this is putting code in OnVisibleChanged, and checking whether the form is visible or not. I didn't really like that... Hope this helps, Geoff P.S. that's all uncompiled 'air code', so there may be typos etc. =================================== This list is hosted by DevelopMentor® http://www.develop.com View archives and manage your subscription(s) at http://discuss.develop.com
