You have forgotten that if A1 and non-A1 are indeed complements of each
other in set A, and so are A1 and A2, then necessarily non-A1 = A2 (and
non-A2 = A1). Thus A1 + non-A1 + A2 + non-A2 = (A1 + non-A2) + (A2 +
non-A1) = (A1 + A1) + (A2 + A2) = A1 + A2 = A. So saying A = A1 + A2 is
equivalent to saying A = A1 + non-A1 + A2 + non-A2, with the only
difference being that one form is redundant.


On Sat, Mar 2, 2013 at 9:28 PM, Piaget Modeler <[email protected]>wrote:

>
> It appears that A is redefined:   A = A1 + non-A1 + A2 + non-A2
>
> So A1 is no longer A non-A2 but something else?
>
> ~PM
>
> ------------------------------
> Date: Sat, 2 Mar 2013 21:13:26 -0600
> Subject: Re: [agi] What if non-A was an entity?
> From: [email protected]
> To: [email protected]
>
>
> How would this change anything?
>
>
> On Sat, Mar 2, 2013 at 8:21 PM, Piaget Modeler 
> <[email protected]>wrote:
>
>
> I'm looking at some literature right now, and am having a mental puzzle.
>
> In a classic Euler or Venn Diagram when we have a circle denoted A, the
> space outside the circle typically represents not-A.
> (see Attachment 1 - affirmations & negations #1).
>
> Consequently if we suppose A is comprised of A1 and A2  (i.e., A = A1 +
> A2), and we say that A1 = A non-A2 or if we say
> that A2 = A non-A1, we are looking at negative space, and subtracting
> either A1 or A2 from the set A (see Attachment 2
> - affirmations & negations #4).
>
> Suppose we make non-A1 and non-A2 explicit (see Attachment 3 -
> affirmations & negations #5).  How does this change things?
> What does A = A1 + A2  now mean?
>
> Your thoughts?
>
> ~PM
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