I don't quite catch the word "inline"

Let me make it a little complex:

Assuming I have a source, for each element A of the source:

if(A.property1 == 1) goes to flow1 + flow2 + flow3
if(A.property1 ==2) goes to  flow4 + flow5
if(A.property1 == 3) goes to flow6 + flow7 + flow8 + flow9
...
...




It seems what I want is a black box composite flow that encapsulate all 
above sub flows and output them in orders.

How should I do branching for above cases?



Leon


在 2015年11月25日星期三 UTC-8上午2:46:25,Akka Team写道:
>
> Hi Leon,
>
> Have you tried not adding a broadcast and try to use it inline?
>
> -Endre
>
> On Wed, Nov 25, 2015 at 10:09 AM, Leon Ma <[email protected] <javascript:>
> > wrote:
>
>> Hi, 
>>
>> I have some questions regarding below code:
>>
>>  val myFlow: Flow[A, B, Any] =
>>     Flow.fromGraph(FlowGraph.create() { implicit b =>
>>       import akka.stream.scaladsl.FlowGraph.Implicits._
>>
>>       val broadcast = b.add(Broadcast[A](2))
>>       val merge = b.add(Merge[B](2))
>>
>>       val flow1 = Flow[A].map(...)
>>       val flow2 = b.add(Flow[A].map(...))
>>
>>       broadcast ~> flow1  ~> merge
>>       broadcast ~> flow2  ~> merge
>>
>>       // expose ports
>>       FlowShape(broadcast.in , merge.out)
>>     })
>>
>>
>> Question:
>>
>> What's the purpose of b.add(...)?  What's the difference if I don't use 
>> it, just like flow1?
>>
>> Thanks
>> Leon
>>
>>
>> -- 
>> >>>>>>>>>> Read the docs: http://akka.io/docs/
>> >>>>>>>>>> Check the FAQ: 
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>
>
>
> -- 
> Akka Team
> Typesafe - Reactive apps on the JVM
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> Twitter: @akkateam
>

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