On Thu, Nov 26, 2015 at 8:30 AM, Leon Ma <[email protected]> wrote:

> I don't quite catch the word "inline"
>

I answered to your original question, why "add" is needed. I wanted to hint
you to try not adding a Broadcast and try it out that way :) (to help
figure out yourself)

Anyway, the simple answer is that every component used in the graph needs
to be added. The only difference is with flows, sinks and sources is that
the library can do it automatically for you, since you don't need to refer
to that flow in a second expression.

To fully wire a broadcast you need two expressions at least, because you
cannot wire both input ports in one expression. Therefore you need a stable
name (a val) to be able to refer to it in those two expressions. This is
not necessary for a flow, which can be wired in one expression: out ~> flow
~> in. It is actually equivalent to out ~> b.add(flow) ~> in. We considered
removing the auto-import feature and requiring explicit addition for
everything.

-Endre



>
> Let me make it a little complex:
>
> Assuming I have a source, for each element A of the source:
>
> if(A.property1 == 1) goes to flow1 + flow2 + flow3
> if(A.property1 ==2) goes to  flow4 + flow5
> if(A.property1 == 3) goes to flow6 + flow7 + flow8 + flow9
> ...
> ...
>
>
>
>
> It seems what I want is a black box composite flow that encapsulate all
> above sub flows and output them in orders.
>
> How should I do branching for above cases?
>
>
>
> Leon
>
>
> 在 2015年11月25日星期三 UTC-8上午2:46:25,Akka Team写道:
>>
>> Hi Leon,
>>
>> Have you tried not adding a broadcast and try to use it inline?
>>
>> -Endre
>>
>> On Wed, Nov 25, 2015 at 10:09 AM, Leon Ma <[email protected]> wrote:
>>
>>> Hi,
>>>
>>> I have some questions regarding below code:
>>>
>>>  val myFlow: Flow[A, B, Any] =
>>>     Flow.fromGraph(FlowGraph.create() { implicit b =>
>>>       import akka.stream.scaladsl.FlowGraph.Implicits._
>>>
>>>       val broadcast = b.add(Broadcast[A](2))
>>>       val merge = b.add(Merge[B](2))
>>>
>>>       val flow1 = Flow[A].map(...)
>>>       val flow2 = b.add(Flow[A].map(...))
>>>
>>>       broadcast ~> flow1  ~> merge
>>>       broadcast ~> flow2  ~> merge
>>>
>>>       // expose ports
>>>       FlowShape(broadcast.in , merge.out)
>>>     })
>>>
>>>
>>> Question:
>>>
>>> What's the purpose of b.add(...)?  What's the difference if I don't use
>>> it, just like flow1?
>>>
>>> Thanks
>>> Leon
>>>
>>>
>>> --
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>>
>>
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>>
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-- 
Akka Team
Typesafe - Reactive apps on the JVM
Blog: letitcrash.com
Twitter: @akkateam

-- 
>>>>>>>>>>      Read the docs: http://akka.io/docs/
>>>>>>>>>>      Check the FAQ: 
>>>>>>>>>> http://doc.akka.io/docs/akka/current/additional/faq.html
>>>>>>>>>>      Search the archives: https://groups.google.com/group/akka-user
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