void putlong(long n)
{
if(n == 0) // special case
{
putchar('0');
return;
}
else
if(n < 0) // if number is negative, print "-" sign and continue as if it
is a positive number
putchar('-'), n = -n;
int arr[30];
int arr_cnt = 0;
while(n)
{
arr[arr_cnt++] = n % 10; // split number into digits
n /= 10;
}
for(int i = arr_cnt-1; i>=0; i--) // print the digits (in reverse order)
putchar(arr[i]+'0');
}
On Thu, Oct 15, 2009 at 9:33 AM, ankur aggarwal <[email protected]>wrote:
> 1. Given only putchar (no sprintf, itoa, etc.) write a routine
> putlong that prints out an unsigned long in decimal.
>
> >
>
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