no need to take care of negative numbers because given number is unsigned long integer ...... apply simple algo :)
On Thu, Oct 15, 2009 at 1:07 PM, Siddharth S <[email protected]> wrote: > > void putlong(long n) > { > if(n == 0) // special case > { > putchar('0'); > return; > } > else > if(n < 0) // if number is negative, print "-" sign and continue as if it > is a positive number > putchar('-'), n = -n; > > int arr[30]; > int arr_cnt = 0; > while(n) > { > arr[arr_cnt++] = n % 10; // split number into digits > n /= 10; > } > for(int i = arr_cnt-1; i>=0; i--) // print the digits (in reverse order) > putchar(arr[i]+'0'); > } > > On Thu, Oct 15, 2009 at 9:33 AM, ankur aggarwal > <[email protected]>wrote: > >> 1. Given only putchar (no sprintf, itoa, etc.) write a routine >> putlong that prints out an unsigned long in decimal. >> >> >> > > > > -- Thanks & Regards Umesh kewat Sent from Hyderabad, AP, India --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---
