there are better solution of O(n) are posted in the thread.......[?].
using order statices ....

On Sun, Mar 28, 2010 at 6:49 PM, Mukesh Kumar thakur <
[email protected]> wrote:

> Create a temp array temp[0..k-1] of size k.
> 2) Traverse the array arr[k..n-1]. While traversing, keep updating the
> smallest element of temp[]
> 3) Return the smallest of temp[]
> Time Complexity: O((n-k)*k).
>
>
> try it ..............for this problem[?]
>
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