Can any one tell how to do this when there are 'm' queries like "query i j
k" find the kth largest element in between indices i->j in an array.
When m is large even an O(n) algorithm would be slow.
I thinking that each query could be answered in O(sqrt(n)) time
So any suggestions ?

Thanks

On Sun, Mar 28, 2010 at 7:57 PM, blackDiamond <[email protected]> wrote:

> there are better solution of O(n) are posted in the thread.......[?].
> using order statices ....
>
>
> On Sun, Mar 28, 2010 at 6:49 PM, Mukesh Kumar thakur <
> [email protected]> wrote:
>
>> Create a temp array temp[0..k-1] of size k.
>> 2) Traverse the array arr[k..n-1]. While traversing, keep updating the
>> smallest element of temp[]
>> 3) Return the smallest of temp[]
>> Time Complexity: O((n-k)*k).
>>
>>
>> try it ..............for this problem[?]
>>
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