Actually the first statement i gave const int i=5; int *ptr=&i is itself
giving an error on gcc and a warning on borland. We have to modify it as
const int *ptr=&i otherwise it gives illegal pointer conversion error.

On Tue, Jun 8, 2010 at 12:11 PM, divya jain <[email protected]>wrote:

> i think both statements shd give error. as u r trying to change int to
> const int in 2 and const int to int in 1..
>
>
> On 7 June 2010 19:59, mohit ranjan <[email protected]> wrote:
>
>> @Raj,
>>
>> no they are not same
>>
>>
>> case 1: i is const
>> case 2: ptr is const
>>
>> and whatever is const cann't be modified
>>
>> Mohit Ranjan
>>
>>
>> On Mon, Jun 7, 2010 at 3:01 PM, Raj N <[email protected]> wrote:
>>
>>> Can someone tell me the difference between
>>> 1) const int i=5;                             2)  int i=5;
>>>   int *ptr=&i;                                      const int
>>> *ptr=&i;
>>>
>>> In the first case i can be modified via ptr i.e *ptr++ is valid. In
>>> the second case *ptr++ is illegal. Why is that so? Aren't they same?
>>>
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