@Raj,

Sorry for the confusion

yes, you are right that 1st one is giving warning/error

though for 2nd case

int i=5;
const int *ptr=&i;
*ptr++;

i am nt getting any error/warning (gcc)  and i remains 5

but
int i=5;
const int *ptr=&i;
(*ptr)++;

is giving error

Mohit Ranjan


On Tue, Jun 8, 2010 at 9:06 PM, Raj N <[email protected]> wrote:

> Actually the first statement i gave const int i=5; int *ptr=&i is itself
> giving an error on gcc and a warning on borland. We have to modify it as
> const int *ptr=&i otherwise it gives illegal pointer conversion error.
>
>
> On Tue, Jun 8, 2010 at 12:11 PM, divya jain <[email protected]>wrote:
>
>> i think both statements shd give error. as u r trying to change int to
>> const int in 2 and const int to int in 1..
>>
>>
>> On 7 June 2010 19:59, mohit ranjan <[email protected]> wrote:
>>
>>> @Raj,
>>>
>>> no they are not same
>>>
>>>
>>> case 1: i is const
>>> case 2: ptr is const
>>>
>>> and whatever is const cann't be modified
>>>
>>> Mohit Ranjan
>>>
>>>
>>> On Mon, Jun 7, 2010 at 3:01 PM, Raj N <[email protected]> wrote:
>>>
>>>> Can someone tell me the difference between
>>>> 1) const int i=5;                             2)  int i=5;
>>>>   int *ptr=&i;                                      const int
>>>> *ptr=&i;
>>>>
>>>> In the first case i can be modified via ptr i.e *ptr++ is valid. In
>>>> the second case *ptr++ is illegal. Why is that so? Aren't they same?
>>>>
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