Why not just change the definition of when one number is bigger than another
and do normal sort ?
I guess that is better and simpler.
--------------------------------------------------
Rohit Saraf
Second Year Undergraduate,
Dept. of Computer Science and Engineering
IIT Bombay
http://www.cse.iitb.ac.in/~rohitfeb14


On Sun, Jun 20, 2010 at 7:52 AM, Anurag Sharma <[email protected]>wrote:

> Keep 2 pointers 'start' and 'end' and make them point to start and
> beginning of the array.
>
> Now keep decresing *end* pointer until an odd element is found
> Keep increasing the *start* pointer until an even element is found
> swap the elements at start and end
> Continue the above 3 steps till start<end
>
> Now the start/end points to a border element which divides the array in 2
> parts, 1st have having all odd numbers and 2nd half with all even numbers.
>
> Now use any inplace sorting algorithm to sort in descending order the
> portion containing all odd numbers and in increasing order the portion
> containing all  even numbers.
> Hope its clear.
>
> Anurag Sharma
>
>
>
> On Sun, Jun 20, 2010 at 2:15 AM, vijay <[email protected]> wrote:
>
>>  There is an array of odd and even numbers. Now, sort them in such a
>> way that the top portion of the array contains odd numbers, bottom
>> portion contains even numbers. The odd numbers are to be sorted in
>> descending order and the even numbers in ascending order. You are not
>> allowed to use any extra array and it has to use a conventional
>> sorting mechanism and should not do any pre or post processing
>>
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