I think in this case, bubble sorting will be a better idea. just
replace the condition of comparison with the condition that earlier
number is even and later number is odd. I mean we can do sumthing lyk
this :
for i=1 to n-1
for j=1 to n-i-1
if iseven(ar[j]) AND (NOT iseven(ar[j+1]))
then swap both of them.
Please correct me if I am wrong somewhere.
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